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Lera25 [3.4K]
3 years ago
15

Which pairs of quadrilaterals can be shown to be congruent using rigid motions?

Mathematics
1 answer:
Elina [12.6K]3 years ago
3 0

Answer:

q1, q2, and q3 are all congruent.

Step-by-step explanation:

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HELP does anyone get these three questions?
Tom [10]

Step-by-step explanation:

since we have the relation (inches/dollars)

4.3 inches down per dollar

per 10 dollars 43 inches down

per half a dollar 2.15 inches down

per 63.60 dollars 273.48 inches down

8 0
3 years ago
Can someone answer this question please please help me I really need it if it’s correct I will mark you brainliest .
Harman [31]

Formula for the perimeter of a quarter circle: C = ((pi x 2r) / 4) + 2r

C = ((3.14 x 18) / 4) + 18

C = (56.52 / 4) + 18

C = 14.13 + 18

C = 32.13 miles

Hope this helps! :)

5 0
3 years ago
fiona draws a 24 centimeter rectangle.gregory draws a 24 square inch rectangle.whose rectangle is in area .how do you know
Valentin [98]

Answer:

Therefore we come to a conclusion that,

Gregory's Rectangle is in Area.

Step-by-step explanation:

Given:

Fiona draws a 24 centimeter rectangle.

Gregory draws a 24 square inch rectangle.

To Find:

Whose rectangle is in area = ?

Solution:

Rectangle has a dimension as

Length and Width which are in meters, centimeters, inches, feet, units, etc.

For Area

Area\ of\ Rectangle=Length\times Width

here units are getting Multiplied so it becomes

unit × unit = unit²  = square units

m × m = m² =square meter

inch × inch = inch² =square inches

Hence Area is calculated in square units.

Therefore we come to a conclusion that,

Gregory's Rectangle is in Area.

6 0
3 years ago
1.) What is the equation of the path of firework #1? Write your equation in general form.
valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in y=ax^2+bx+c

it's easier to find vertex form first then expand to get general form

vertex form is y=a(x-h)^2+k where the vertex is (h,k) and a is a constant


firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

h_1=a(t-10)^2+50

to find the value of a, subsitute another point

(0,0)

0=a(0-10)^2+50)

0=100a+50

a=\frac{-1}{2}

so the equation in vertex form is h_1=\frac{-1}{2}(t-10)^2+50

expand to get general form

h_1=\frac{-1}{2}(t^2-20t+100)+50

h_1=\frac{-1}{2}t^2+10t-50+50

h_1=\frac{-1}{2}t^2+10t





2.

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is h_2=a(t-10)^2+72

find a

use another point

(0,22)

22=a(0-10)^2+72

22=100a+72

-50=100a

a=\frac{-1}{2}

so the equation in vertex form is h_2=\frac{-1}{2}(t-10)^2+72




3.

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50


domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0
3 years ago
Your neighbor asks you to feed her cat and water her plants while she is on vacation. she pays you c dollars to feed her cat per
Dmitry [639]

Answer:

cx + wx

Step-by-step explanation:

6 0
3 years ago
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