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Westkost [7]
3 years ago
9

Define one metre length.​

Physics
1 answer:
OleMash [197]3 years ago
4 0

Answer:

The metre is currently defined as the length of the path travelled by light in a vacuum in 1299 792 458 of a second

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Which of the following is a high wave that crashes down onto the
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A breaker is a high wave that crashes onto the ocean floor.
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Within a pendulum, as kinetic energy decreases, potential energy _____.
romanna [79]

Answer: a

Increase

Explanation:

Simple pendulum motion obeys law of conservative of energy. Where at maximum K.E, P.E = 0 and vice versa.

Also, increase in K.E will lead to decrease in P.E and vice versa.

5 0
3 years ago
Radar uses radio waves of a wavelength of 2.2 m . The time interval for one radiation pulse is 100 times larger than the time of
liq [111]

Answer:

<em>The shortest distance to an object that this radar can detect would be </em>

<em>111 m</em>

Explanation:

The shortest distance is the minimum distance that would be detected by the radar, The time of oscillation can be obtained thus;

T = 1/f   ..........1

but f= v/λ substituting f into equation 1 we have;

T = λ/v...............2

Where λ is the wavelength = 2.2 m

v is the velocity of  light  since the radar is an electromagnetic wave

   = 3 x10^{8} m/s

T = 2.2 m / 3 x10^{8} m/s

T = 7.33 x10^{-9} s

<u>Calculating the time interval required by the pulse</u>

Since the interval of the pulse (t) is 100 times greater than the period of oscillation, the time of the pulse is expressed as;

t = 100 x T

t = 100 x 7.33 x10^{-9} s

t = 7.33 x 10^{-7} s

Therefor the time of the pulse is 7.33 x 10^{-7} s

<u>Calculating for the shortest distance of the radar</u>

The shortest distance of the radar can be obtained using the equation below;

λ_s = (t/2) x v ............3

Substituting into equation 3 we have

λ_s = (7.33 x 10^{-7} /2) x 3 x10^{8} m/s

λ_s  =  111 m

Therefore the shortest distance to an object that this radar can detect would be 111 m

   

8 0
3 years ago
A long, thin rod (length = 4.0 m) lies along the x axis, with its midpoint at the origin. In a vacuum, a +8.0C point charge is f
alexandr1967 [171]

Answer:

256 x 10³ Nm

Explanation:

Force on each of the charges of 8 C due to uniform electric field in x -y plane  will be equal and opposite because one is positive charge and the other is negative charge. They will make a couple

Each of the forces of the couple will act in x - y plane and will be equal to

F = Q E = 8 X 8 X 10³

= 64 X 10³ N

Arm of the couple = 4 m

Moment of couple about z axis.

= 64 x 10³ x 4

= 256 x 10³ Nm.

5 0
3 years ago
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