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3 years ago

What are some examples of aerobic exercise?

Physics

1 answer:

Firdavs [7]3 years ago

4 0

Answer:

swimming, cycling, and jogging

Explanation:

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Write the energy conversion when climbing a ladder

Volgvan

A child climbing a ladder is transforming kinetic energy into potential energy.

7 0

2 years ago

Se coloca una piedra de 600 g en una Honda de 50 cm y se la hace girar a una velocidad de 4 m/s. Dibuja la fuerza que ejerce la

Dima020 [189]

Answer:

Fc = 19.2 N

Explanation:

In this case, the force of the Honda over the rock, is a centripetal force. Then, you have:

$F_c=m\frac{v^2}{r}$

m: mass of the rock = 600g = 0.6 kg

v: tangential velocity of the Honda = 4m/s

r: radius of the Honda = 50cm = 0.5m

You replace the values of m, r and v in the equation for Fc:

$F_c=(0.6kg)\frac{(4m/s)^2}{0.5m}\\\\F_c=19.2N$

hence, the force has a magnitude of 19.2 N

If the rock would have more mass the centripetal force would be higher

4 0

3 years ago

How do you find the total magnification of a microscope?

Alla [95]

In order to find total magnification of a microscope, you need to multiply the power of eyepiece and objective lens.

Hope this helps!

6 0

3 years ago

Using the rules for the significant figures what do you get when you add 24.545 and 307.3

Tamiku [17]

1
2 4. 5 4 5
+3 0 7. 3 0 0
——————
3 3 1 8 4 5
line up the decimal points and add.
hope this helps!

4 0

3 years ago

A boat race runs along a triangular course marked by buoys A, B, and C. The race starts with the boats headed west for 3700 mete

ale4655 [162]

Answer:

The last two bearings are

49.50° and 104.02°

Explanation:

Applying the Law of cosine (refer to the figure attached):

we have

x² = y² + z² - 2yz × cosX

here,

x, y and z represents the lengths of sides opposite to the angels X,Y and Z.

Thus we have,

$cos X=\frac{x^2-y^2-z^2}{-2yz}$

$cos X=\frac{y^2 + z^2-x^2}{2yz}$

substituting the values in the equation we get,

$cos X=\frac{2900^2 + 3700^2-1700^2}{2\times 2900\times 3700}$

$cos X=0.8951$

X = 26.47°

similarly,

$cos Y=\frac{1700^2 + 3700^2-2900^2}{2\times 1700\times 3700}$

$cos Y=0.649$

Y = 49.50°

Consequently, the angel Z = 180° - 49.50 - 26.47 = 104.02°

The bearing of 2 last legs of race are angels Y and Z.

7 0

3 years ago