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Mrrafil [7]
3 years ago
8

A car accelerates from 6.0 m/s to 18 m/s at a rate of 3.0 m/s2. How far does it travel while accelerating

Physics
1 answer:
AlekseyPX3 years ago
4 0

Answer:

48m, hope this helps :)

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A. If we increase the wind velocity, the maximum vertical dispersal height and rate of diffusion will decrease____.
vovikov84 [41]

Answer:

a.If we increase the wind velocity, the maximum vertical dispersal height will decrease, while the rate of diffusion will increase

b.If we increase the humidity, the maximum vertical dispersal height will increase after 24 hours.

c.If we increase the lapse rate, the maximum vertical dispersal height of the pollutants will increase

Explanation:

a.If we increase the wind velocity, the maximum vertical dispersal height will decrease, while the rate of diffusion will increase

b.If we increase the humidity, the maximum vertical dispersal height will increase after 24 hours.

c.If we increase the lapse rate, the maximum vertical dispersal height of the pollutants will increase

8 0
3 years ago
Read 2 more answers
Eating an orange enables a person to perform about 3.5x10^4 J of work. To what height does eating and orange enable a 55kg woman
crimeas [40]
Joules is a unit for work which may decomposed into N.m. Work is a quantity which is a product of force (in this case, the woman's weight) and the distance she has traveled. 
 
                                    W = F x d      ;    d = W / F

Substituting the given, 
  
                             d = (3.5 x 10^4 J) / (55 kg x 9.8 m/s²) = 64.94 m

Thus, the woman can climb up to 64.94 meters. 

3 0
3 years ago
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Does the diagram show a spring or neap tide?How do you know?
vampirchik [111]
It shows a neap tide 
6 0
3 years ago
Is the force of friction the sum of all the microscopic contact forces between the bottom of the block and the surface?
kotegsom [21]

The force of friction is that force that tends to oppose the motion of the body with the surface in contact... are you clear with it?

6 0
2 years ago
A roller coaster starts from rest at its highest point and then descends on its (frictionless) track. Its speed is 36 m/s when i
Ganezh [65]

Answer:

its speed when its height was half that of its starting point is 25.46 m/s

Explanation:

Given;

final speed of the roller coaster, v = 36 m/s

Applying general equation of motion;

V² = U² + 2gh

where;

V is the final speed of the roller coaster

U is the initial speed of the roller coaster = 0

h is the height attained at a given velocity

36² = 0 + (2 x 9.8)h

1296 = 19.6 h

h = 1296/19.6

h = 66.1224 m

when its height was half that of its starting point, h₂ = ¹/₂ h

h₂ = ¹/₂(66.1224 m) = 33.061 m

At h = 33.061 m, V = ?

V² = U² + 2gh

V² = 0 + 2 x 9.8 x 33.061

V² = 648

V = √648

V = 25.46 m/s

Therefore, its speed when its height was half that of its starting point is 25.46 m/s

8 0
3 years ago
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