A car accelerates from 6.0 m/s to 18 m/s at a rate of 3.0 m/s2. How far does it travel while accelerating

You are on an airplane traveling 30° south of due west at 180 m/s with respect to the air. The air is moving with a speed 31 m/s

BlackZzzverrR [31]

1) 211m/s
2)240<span>°
3)759,600m or 759.6 km</span>

6 0

4 years ago

A student uses a spring with a spring constant of 130 N/m in his projectile apparatus. When 56 J of

Triss [41]

Explanation:

$potentional \: energy \: = \frac{1}{2} k {x}^{2} \\ 56 = \frac{1}{2} \times 130 \times {x}^{2} \\ {x}^{2} = \frac{56}{65} \\ x = \sqrt{ \frac{56}{65} } meter$

plz..

mark it as a brilliant answer

4 0

3 years ago

A charge of 5.4 C experiences a force of 25.0 in an electric field. What is the strength of electric field at that point ? If th

Airida [17]

The strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.

<h3></h3><h3>What is the electric field strength?</h3>

The electric field strength is defined as the ratio of electric force to charge.

Given data;

q₁ = 5.4 C

F₁ is the electric force in case1

E is the electric field =?

F₂ is the electric force in case 2

q₂ is the charge 2

The strength of the electric field at that point is;

F₁=Eq₁

E₁=F/q₁

E₁=25.0 N / 5.4 C

E₁=4.587 N/C

The force would this charge experience at that point when the charge is 2.7 C;

F₂=Eq₂

F₂=4.587 N/C × 2.7 C

F₂ = 12.38 N

Hence the strength of the electric field at that point and the force would this charge experiences at that point will be 4.587 N/C and 12.38 N.

To learn more about the electric field strength, refer to the link;

brainly.com/question/4264413

#SPJ1

8 0

2 years ago

An air-track glider undergoes a perfectly inelastic collision with an identical glider that is initially at rest. what fraction

DiKsa [7]

Refer to the diagram shown below.

The initial KE (kinetic energy) of the system is
KE₁ = (1/2)mu²

After an inelastic collision, the two masses stick together.
Conservation of momentum requires that
m*u = 2m*v
Therefore
v = u/2

The final KE is
KE₂ = (1/2)(2m)v²
= m(u/2)²
= (1/4)mu²
= (1/2) KE₁

The loss in KE is
KE₁ - KE₂ = (1/2) KE₁.

Conservation of energy requires that the loss in KE be accounted for as thermal energy.

Answer: 1/2

5 0

4 years ago

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As a car accelerates its tires increase their angular velocity from 114 rad/s to 131 rad/s in 0.43 seconds. What is the angular

e-lub [12.9K]

I think it's 39.53

(please do calculate it. I am not completely sure)

5 0

3 years ago

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