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Lisa [10]
2 years ago
6

Which comparison is correct? 7 -7 -9 > 4 -6 > -5

Mathematics
1 answer:
ArbitrLikvidat [17]2 years ago
8 0

Answer:

7 > -7

Step-by-step explanation:

-9 is not greater than -4

-6 is not greater than -5

I am not sure what 7 -7 means in your first option but if it is consistent, then yes, 7 is greater than -7.

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Please help me Answer the encircled numbers only
MrRissso [65]
I hope this helps you

3 0
2 years ago
Type the solution.y=–3x–7y=x–3
Andrej [43]

Answer:

(x,y)=(-1,-4)

Step-by-step explanation:

y=–3x–7

y=x–3

(y=)-3x-7=x-3

-3x-x=-3+7

-4x=4

x=4/(-4)

x=-1

y=x-3

y=-1-3

y=-4

(x,y)=(-1,-4)

6 0
2 years ago
Please, Please help ASAP
BlackZzzverrR [31]

Answer:

5 is the answer

please mark as brainlist

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7 0
2 years ago
Read 2 more answers
The diameter of a circle has endpoints P(-12, -4) and Q(6, 12).
nexus9112 [7]

9514 1404 393

Answer:

  (x +3)² +(y -4)² = 145

Step-by-step explanation:

The center of the circle is the midpoint of the given segment PQ. If we call that point A, then ...

  A = (P +Q)/2

  A = ((-12, -4) +(6, 12))/2 = (-12+6, -4+12)/2 = (-6, 8)/2

  A = (-3, 4)

The equation of the circle for some radius r is ...

  (x -(-3))² +(y -4)² = r² . . . . . . where (-3, 4) is the center of the circle

The value of r² can be found by substituting either of the points on the circle. If we use Q, then we have ...

  (6 +3)² +(12 -4)² = r² = 9² +8²

  r² = 81 +64 = 145

Then the equation of the circle is ...

  (x +3)² +(y -4)² = 145

3 0
3 years ago
9/20
NISA [10]

For this case we must find the solution of the following quadratic equation:

x ^ 2 + 5x + 7 = 0

Where:

a = 1\\b = 5\\c = 7

Then, the solution is given by:

x = \frac {-b \pm \sqrt {b ^ 2-4 (a) (c)}} {2a}

Substituting the values:

x = \frac {-5 \pm \sqrt {5 ^ 2-4 (1) (7)}} {2 (1)}\\x = \frac {-5 \pm \sqrt {25-28}} {2}\\x = \frac {-5 \pm \sqrt {-3}} {2}

By definition we have:i ^ 2 = -1

x = \frac {-5 \pm \sqrt {3i ^ 2}} {2}\\x = \frac {-5 \pm i \sqrt {3}} {2}

Thus, we have two complex roots.

Answer:

The equation has no real roots.

4 0
3 years ago
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