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3 years ago

Please help me with this question!!

Mathematics

1 answer:

tester [92]3 years ago

5 0

Answer:

Step-by-step explanation:

Pythagorean Theorem is "a^2+b^2=c^2"

Step 1) 1^2+6^2=37

37=c^2

Step 2) The square root of 37 is 6.08

That's not 9

So they don't form a Pythagorean triple

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Which expression is equivalent to (4x^(3)y^(5))(3x^(5)y)^(2)

marshall27 [118]

Answer:

$(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7$

Step-by-step explanation:

Given

$(4x^3y^5)(3x^5y)^2$

Required

The equivalent expression

We have:

$(4x^3y^5)(3x^5y)^2$

Expand

$(4x^3y^5)(3x^5y)^2 = 4x^3y^5*9x^{10}y^2$

Further expand

$(4x^3y^5)(3x^5y)^2 = 4*9*x^3*x^{10}y^5*y^2$

Apply laws of indices

$(4x^3y^5)(3x^5y)^2 = 36*x^{13}y^7$

8 0

3 years ago

If s and t are integers greater than 1 and each is a factor of the integer n, which of the following must be a factor of n st ?

yulyashka [42]

Answer:

A) None

Step-by-step explanation:

1) $s^t$ shoudnt neccesarily be a factor of nst, for example, if s = 3, t = 4, and n = 12, then both s and t are factors of n, but $3^4 = 81$ is not a factor of nst = 144.

2) $(st)^2$ shoudnt neccesarily be a factor of nst. Let s be 4, let t be 6, and let n be 12. Then n is a factor of both s and t, but $(st)^2 = 24^2$ is not a factor of nst = 12*24. In fact, it is a greater number.

3) Again, s+t isnt necessarily a factor of nst, let s be 2 and t be 3. Then both s and t are factor of n = 12. However 5 = s+t is not a factor of nst = 72.

So, neither of the three options is guaranteed to be a factor of nst. In fact, for s = 4, t = 6, and n = 12, none of the three options are valid.

4 0

3 years ago

1.901 x 10^-7 in standard notation

WITCHER [35]

Answer:

In standard form, it would be 0.0000001901!

Step-by-step explanation:

As you can see, if the exponent is negative, the answer would be a decimal so moving the decimal place 7 times to the left, that would be your answer.

7 0

3 years ago

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Sholpan [36]

Answer:

The equation of the line in slope-intercept form is: