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3 years ago

Find 64.9% of 77. Round to the nearest tenth.

Mathematics

2 answers:

Levart [38]3 years ago

7 0

The answer would be 64.9% of 77 is 49.973 then when you round it to the nearest tenth it will give you 50

Answer : 50

eduard3 years ago

6 0

Answer:

64.9% of 77

Step-by-step explanation:

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What's the slope intercept of 6+x=2y

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The answer to your problem is 1/2!

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3 years ago

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2. b = 10 feet area = 35 feet 2 Find the height of the triangle

Andreyy89

Answer:

Height = 7

Step-by-step explanation:

35*2

70/10

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3 years ago

One tank is filling at a rate of

jeka57 [31]

Answer:

The answer is the 59 gallons per 13 minutes.

Step-by-step explanation:

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3 years ago

At NC State University, 16.4% of the undergraduate classes have more than 50 students. If a random sample of 200 undergraduate c

Lena [83]

Answer:

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=200, p=0.164)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

We need to check the conditions in order to use the normal approximation.

$np=200*0.164=32.8 \geq 10$

$n(1-p)=200*(1-0.164)=167.2 \geq 10$

The population proportion have the following distribution

$p \sim N(p,\sqrt{\frac{p(1-p)}{n}})$

The mean is given by:

$p =0.164$

And the deviation is given by:

$\sigma_{p}= \sqrt{\frac{0.164*(1-0.164)}{200}}= 0.0262$

So then the correct options for this case are:

The sampling distribution will be approximately normal.

The mean of the sampling distribution will be 16.4%.

The standard deviation of the sampling distribution will be 0.0262.

6 0

3 years ago

How many terms are there in a geometric series if the first term is 7, the common ratio is 2, and the sum of the series is 105?

uysha [10]

105 = 7. (1 - 2^n) / 1-2

105*-1 = 7 (1 - 2^n)

1 - 2^n = -105/7 = - 15

2^n = 16

n = 4 answer

4 0

4 years ago