We shall use the formula for distance traveled:
s = ut + (1/2)at^2
where
u = initial velocity
t = time
a = acceleration.
Because
u = 0 (car starts from rest),
t = 10 s (travel tme),
a = 2 m/s^2 (acceleration), m
the di mstance traveled is
s = (1/2)*(2 m/s^2)*(10 s)^2 = (1/2)*2*100 = 100
Answer: 100 m
2x+3y= -17
5x+2y= -4
You must cancel either the x or y out to solve so i'm going to cancel the x.
-5(2x+3y= -17)
2(5x+2y= -4)
This simplifies to:
-15x -15y=85
15x+4y= -8
The -15x and 15x cancel out leaving you:
-15y=85
4y= -8
You add them top numbers by the bottom and get:
-11y=77
Then divide by -11 to get y by its self.
y= -7
Now that you know what y is just plug it in to either original problem. I will use the second one.
5x + 2(-7) = -4
5x -14 = -4
5x = 10
x = 2
So the answer is (2,-7) or x=2 and y=-7
Answer:
the answer is a where x=8
Explanation:
cross multiplication method
Answer:
h= 12/pi OR 3.81972
Step-by-step explanation:
Answer:
y = 5x - 21
Step-by-step explanation:
Since we already know the slope, all we need to do is plug the values of x and y into the equation.
y = 5x + b
-1 = 5(4) + b
-1 = 20 + b
-21 = b
The equation is y = 5x - 21.
