Our aim is to calculate the Radius so that to use the formula related to the area of a segment of a circle, that is: Aire of segment = Ф.R²/2
Let o be the center of the circle, AB the chord of 8 in subtending the arc f120°
Let OH be the altitude of triangle AOB. We know that a chord perpendicular to a radius bisects the chord in the middle. Hence AH = HB = 4 in
The triangle HOB is a semi equilateral triangle, so OH (facing 30°)=1/2 R. Now Pythagoras: OB² = OH² + 4²==> R² = (R/2)² + 16
R² = R²/4 +16. Solve for R ==> R =8/√3
OB² = OH² +
So you do
distribute
a(b+c)=ab+ac
9(x+5)=9x+9 times 5=9x+45
7(x-3)=7x+7 times -3=7x-21
so now we have
9x+45+7x-21
group like terms
9x+7x+45-21
add
16x+24
simplified is 16x+24
x intercept is calculated by putting y = 0 in equation which gives us x = 3.
so option 4
Answer:
7(top left) 5(top right)
6(bottom left) 0(bottom right)
Answered by GAUTHMATH
Answer:
13 units
Step-by-step explanation:
-1 + (-8) = -9
|-9| = 9 + 4 = 13
(-9) is 13 units from 4
Hopefully this helps you :)
pls mark brainlest ;)
