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alexira [117]
2 years ago
8

Find the volume of a right circular cone that has a height of 11.4 in and a base with a radius of 5.1 in. Round your answer to t

he nearest tenth of a cubic inch.
Mathematics
1 answer:
ella [17]2 years ago
5 0

Answer:

Step-by-step explanation:

h=11.4 in

r=5.1 in

v=3.14*r^2*(h/3)

V=3.14*5.1^2*(11.4/3)=3.14*26.01*3.8=310.35

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Elodia [21]
Just divide

3/4 = 0.75

4 teachers, and only 3 gallons of paint
1 less gallon of paint, so each teacher should get less than a whole. 

0.75 gallons of paint per teacher
5 0
3 years ago
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Using the formula for simple interest and the given values, find I. P= $300; r = 8%; t= 6 years; I = ? 1=$0 TrueCar Enter your a
Mashutka [201]

Answer: $144

Step-by-step explanation:

The formula to calculate the simple interest is given by :-

\text{S.I.}=Prt

Here, P - Principal amount, r - rate of interest and t is time (Generally in years).

Given :  P= $300; r = 8%=0.08 ; t= 6 years

Now, the using the above simple interest formula , we have

\text{I}=300\times0.08\times6\\\\\Rightarrow\ \text{I}=\$\ 144

Therefore , the simple interest = $ 144.

6 0
3 years ago
Given below is the even-number function. Which of the following are equal to E(12)? Check all that apply. E(n) = 2n A. 24 B. E(6
Ray Of Light [21]
Ummmm i believe your answer is A. just divide next time :)
4 0
3 years ago
A 41 gram sample of a substance that's used to detect explosives has a k-value of 0.1392. Find the substance's half life, in day
-BARSIC- [3]

Answer:

The substance half-life is of 4.98 days.

Step-by-step explanation:

Equation for an amount of a decaying substance:

The equation for the amount of a substance that decay exponentially has the following format:

A(t) = A(0)e^{-kt}

In which k is the decay rate, as a decimal.

k-value of 0.1392.

This means that:

A(t) = A(0)e^{-0.1392t}

Find the substance's half life, in days.

This is t for which A(t) = 0.5A(0). So

A(t) = A(0)e^{-0.1392t}

0.5A(0) = A(0)e^{-0.1392t}

e^{-0.1392t} = 0.5

\ln{e^{-0.1392t}} = \ln{0.5}

-0.1392t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.1392}

t = 4.98

The substance half-life is of 4.98 days.

5 0
3 years ago
What is the value of x in the figure shown
LiRa [457]

Answer:

x = 66

Step-by-step explanation:

Have a nice day

7 0
3 years ago
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