Answer:
draw 5 tomatoes at the top and below that draw 2 cucumbers then next to it draw 10 tomatoes and 4 cucumbers. 4/9 4 for every 9
Step-by-step explanation:
3 + 6 + 9 + 12 + ... + 999
<span>= 3(1 + 2 + 3 + 4 + ... + 333) </span>
<span>= 3(Summation of r from 1 to 333) </span>
<span>= 3((1 + 333)(333/2)) </span>
<span>= 3(334)(333/2) </span>
<span>= 3(167)(333) </span>
<span>= 166833 </span>
<span>Edit: Opps, I forgot that you ask about an equation. </span>
<span>The sum of 1 + 2 + 3 + 4 + ... + n, where n is some integer, is: </span>
<span>(First term + Last term) multiplied by (Total number of terms / 2) </span>
<span>= (1 + n)(n / 2)</span>
Step-by-step explanation:
Mark her brainliest dude!!!!
Answer:
![m = 3 \sqrt{12}](https://tex.z-dn.net/?f=m%20%3D%203%20%5Csqrt%7B12%7D%20)
![n = 6](https://tex.z-dn.net/?f=n%20%3D%206)
Step-by-step explanation:
n=1/2 of 12 according to the rule:
right triangle the side opposite the 30 degree angle is half the length of the hypotenuse.
so n=12/2=6
and now we will need Pythagorean theorem : the sum of the squares on the legs of a right triangle is equal to the square on the hypotenuse (the side opposite the right angle)—or, in familiar algebraic notation, a2 + b2 = c2.
so
![{m}^{2} + {n}^{2} = {12}^{2}](https://tex.z-dn.net/?f=%20%7Bm%7D%5E%7B2%7D%20%20%2B%20%20%20%7Bn%7D%5E%7B2%7D%20%20%3D%20%20%7B12%7D%5E%7B2%7D%20)
now lets put numbers on formula
![{m}^{2} + {6}^{2} = {12}^{2}](https://tex.z-dn.net/?f=%20%7Bm%7D%5E%7B2%7D%20%20%2B%20%20%7B6%7D%5E%7B2%7D%20%20%3D%20%20%7B12%7D%5E%7B2%7D%20)
from this formula m=
![m = \sqrt{ {12}^{2} - {6}^{2} } = \sqrt{144 - 36} = \sqrt{108} = 3 \sqrt{12}](https://tex.z-dn.net/?f=m%20%3D%20%20%5Csqrt%7B%20%7B12%7D%5E%7B2%7D%20%20%20-%20%20%20%7B6%7D%5E%7B2%7D%20%7D%20%20%20%3D%20%20%5Csqrt%7B144%20-%2036%7D%20%20%3D%20%20%5Csqrt%7B108%7D%20%20%3D%203%20%5Csqrt%7B12%7D%20)