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Monica [59]
3 years ago
12

HELP I NEED HELP ASAP

Mathematics
1 answer:
Elodia [21]3 years ago
4 0

Answer:

its C

Step-by-step explanation:

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Number of Bars
Montano1993 [528]

Answer: Disagree. 1 in 8 bars are cinnamon.

Step-by-step explanation:

There are a total of 8 bars in the pack. Cinnamon is 1 of the 8. Therefore, for every 8 bars, one is cinnamon.

7 0
3 years ago
-(2)negative negative two quotation to the zero power equals ​
MakcuM [25]

Answer:

1

Step-by-step explanation:

While I am not 100% sure what you are putting (I'm assuming it's -2^0), anything to the power of 0 will equal a positive 1 as your answer.

5 0
3 years ago
Helena is purchasing a house for $210000
cricket20 [7]

what is the full question



6 0
3 years ago
Cynthia invests some money in a bank which pays
USPshnik [31]

Let ,Cynthia invested $x

Rate = 5%per year

time = 3 year

Amount

A= P(1+r/100)^t

8000=x(1+5/100)^3

8000=x(21/20)^3

x= (8000x8000)/9261

x=6910.7$

Therefore she can invest =$6910.7 =5322.14 pound  

4 0
3 years ago
A marketing firm would like to test-market the name of a new energy drink targeted at 18- to 29-year-olds via social media. Supp
Trava [24]

Answer:

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

Step-by-step explanation:

As the test is targeted to 18-to-29-year-old adults using  social media, we want to know the probability that a randomly selected adult uses social media and belong to the study group.

To achieve this, we have this data:

- 36% of all adults do not use social media

- 75% of all adults are >30 years old.

- The percentage of population that is <em>either</em> 18-29 years old <em>or</em> uses social media is 66.7%

Using the last data we have that

P(social\,media=yes\, or\,18-29=yes)=P(social\,media=yes)+P(18-29=yes)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=(1-0.36)+(1-0.75)-P(social\,media=yes\, \&\,18-29=yes)\\\\0.667=0.64+0.25-P(social\,media=yes\, \&\,18-29=yes)\\\\P(social\,media=yes\, \&\,18-29=yes)=0.64+0.25-0.667=0.223

The probability of randomly select an adult that has between 18 and 29 years old and use social media is 22.3%

8 0
3 years ago
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