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Taya2010 [7]
3 years ago
13

Fill in the table below

Mathematics
1 answer:
pickupchik [31]3 years ago
5 0

Answer:

60_1hrs

30min-?

30 min-1 1/2

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I need the answer for both of them I’ll give your Brainly help
ExtremeBDS [4]

Answer:

11. a)50      12. a)40

Step-by-step explanation:

sum of  all three angles of  trinagle=180

so

111.

80+50+x=180

130+x=180

x=180-130

x=50

12.

60+90+x=180

150+x=180

x=190-150

x=40

4 0
3 years ago
Read 2 more answers
Need help with this!
adell [148]

9514 1404 393

Answer:

  a(n) = 1/2(-8)^(n-1)

Step-by-step explanation:

The general term of a geometric sequence is ...

  a(n) = a(1)×r^(n-1)

where a(1) is the first term, and r is the common ratio.

Here, the first term is a(1) = 1/2. The common ratio is the ratio of any two sequential terms: r = 32/-4 = -8. Then the explicit formula is ...

  a(n) = 1/2(-8)^(n-1)

3 0
3 years ago
X+6/x+2=x+3/x-5 how do i solve ?
mr Goodwill [35]

Answer:

just do the cross multiplication method

6 0
3 years ago
Can someone do this? Ty
Blababa [14]

Answer:

Step-by-step explanation:

C)   Sarah is trying to say that 72 and 64 are opposite, if 68 is used as the starting point.  So from the point 68,   72 is +4 and 64 is -4.   68 is the "baseline"   or starting point

6 0
3 years ago
Suppose that the probability of suffering a side effect from acertain flu vaccine is 0.005. If 1000 persons are inculated, finda
aniked [119]

Answer:

The answers to the question are

a) The probability that at most 1 person suffers side effect from the flu vaccine is 4.043×10⁻²

b) The probability that 4,5,or 6 persons suffer side effect from the flu vaccine is 0.49716.

Step-by-step explanation:

We solve the question using the formula for Poisson probability as follows

Let the probability of suffering a side effect from a certain flu vaccine be p

we have n = 1000 and p = 0.005

then by binomial theorem μ = 1000*0.005 = 5

using  Poisson probability formula, we haveP(X=k) =\frac{\lambda ^k e^{-\lambda}}{k!}

where λ = μ

for P(X=0) we have \frac{5^0e^{-5}}{0!} = 6.73×10⁻³

P(X=1) we have \frac{5^1e^{-5}}{1!} = 3.37×10⁻²

Using the addition rule, we have

P (X≤1) = P(X=0) + P(X=1) =  6.73×10⁻³ + 3.37×10⁻² = 4.043×10⁻²

b) Similarly, we have for k = 4, 5, 6 we have

P(X=4) we have \frac{5^4e^{-5}}{4!} =0.1755

P(X=5) we have \frac{5^5e^{-5}}{5!} = 0.1755

P(X=6) we have \frac{5^6e^{-5}}{6!} =0.14622

Therefore P(X=4) or P(X=5), P(X=6)  is given by

0.1755 + 0.17546 + 0.14622 = 0.49716

4 0
3 years ago
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