All categories

2 years ago

Find the output, y, when the input, , is -1. Y =

Mathematics

1 answer:

kozerog [31]2 years ago

4 0

Answer:

To find output add 1.5 to every input number. Hopefully this helps

Step-by-step explanation:

You might be interested in

Can you give me the answer to this

Nitella [24]

Answer: I think A

Step-by-step explanation:

6 0

2 years ago

Three consecutive even numbers add up to a number between 100 and 120 what might the number be?

Rzqust [24]

The number can be 102, 108, or 114. They can all be formed that way.

32 + 34 + 36 = 102
34 + 36 + 38 = 108
36 + 38 + 40 = 114

The next one is 120 . . . . . 38 + 40 + 42

7 0

2 years ago

two irregular pentagons are constructed so that every side has length of 1 unit. Does this necessarily mean that these figures a

algol [13]

Answer:

la repuedta es la tila idnjxnfozmsuzndybdjsnshsbsb

5 0

2 years ago

Factor completely x^2 - 3x - 28

lbvjy [14]

Answer:

(x-7) (x+4)

Step-by-step explanation:

x^2 - 3x - 28

What two numbers multiply to -28 and add to -3

-7*4 = -28

-7+4 = -3

(x-7) (x+4)

5 0

2 years ago

Read 2 more answers

) An instructor gives his class a set of 18 problems with the information that the next quiz will consist of a random selection

RSB [31]

Answer:

The probability the he or she will answer correctly is 1.5%

Step-by-step explanation:

In all, there are 18 problems. In this question, the order of which the problems are sorted for the quiz makes no difference. For example, if the question A of the quiz is P1 and question B P2, and question A P2 and question B P1, it is the same thing.

There are 18 problems and 9 are going to be selected. So, there is going to be a combination of 9 elements from a set of 18 elements.

A combination of n elements from a set of m objects has the following formula:

$C_{(m,n)} = \frac{m!}{n!(m-n)!}$

In this question, m = 18, n = 9. So the total number of possibilities is:

$T_{p} = C_{(18,9)} = \frac{18!}{9!(18-9)!} = 48620$

Now we have to calculate the number of desired outcomes. This number is a combination of 9 elements from a set of 13 elements(13 is the number of problems that the student has figured out how to do).

Now, m = 13, n = 9. The number of desired possibilities is:

$D_{p} = C_{(13,9)} = \frac{13!}{9!(13-9)!} = 715$

The probability is the number of desired possibilities divided by the number of total possibilities. So

$P = \frac{715}{48620} = 0.015 = 1.5%$

The probability the he or she will answer correctly is 1.5%

3 0

2 years ago