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dlinn [17]
3 years ago
15

The function f(x)=3x+12x+11 can be written in vertex form as?

Mathematics
1 answer:
solmaris [256]3 years ago
7 0
 y = -3(x<span> - 2)^2 + 1 </span>x<span>-coordinate of vertex: </span>x<span> = -b/(2a) = -12/-6 = 2 y-coordintae of vertex: y(2) = -12 + 24 - 11 = 1 </span>Vertex form: y = -3(x<span> - 2)^2 + 1 Check. Develop y to get back to standard form: y = -3(</span>x^2 - 4x + 4) + 1 = -3x<span>^2 + </span>12x<span> - </span>11<span>. </span>
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Which of the following can be represented by the expression 2 ➗ (1/3)? a. Faye has 2 yards of twine and uses (1/3) yard to tie a
GREYUIT [131]

Answer: C. She is dividing the entire length into shorter lengths.

The rest of the question would be "How many pieces will she get?"

Step-by-step explanation:

A would be a subtraction problem UNLESS it goes on to ask "how many 1/3 yard pieces can she cut?"

It's a subtraction problem if it's about "how many yards are left?"

B is just backwards and makes no sense with the expression given.

7 0
3 years ago
What’s the equation in vertex form?
pshichka [43]

Answer:

\large\boxed{y=(x+5)^2-64}

Step-by-step explanation:

\text{The vertex form of equation}\ y=ax^2+bx+c:\\\\y=a(x-h)^2+k\\\\h=\dfrac{-b}{2a},\ k=f(h)\\\\\text{We have the equation:}\ y=x^2+10x-39\to x=1,\ b=10,\ c=-39.\\\\\text{Substitute:}\\\\h=\dfrac{-10}{2(1)}=\dfrac{-10}{2}=-5\\\\k=f(-5)=(-5)^2+10(-5)-39=25-50-39=-64\\\\\text{Finally:}\\\\y=1(x-(-5))^2-64=(x+5)^2-64

8 0
3 years ago
Anderson uses the discriminant to correctly find the number of real solutions of the quadratic equation one-halfx2 + 4x + 8 = 0.
amid [387]

Answer:

The discriminant of ax^2+bx+c is b^2-4ac.  

If the discriminant, d, is:

d<0, there are no real solutions (there are two imaginary solutions however)

d=0, there is one real solution

d>0, there are two real solutions

In this case d=16-32=-16 so there are two imaginary solutions.  Or from your answer choices, it can be said that there are no real number solutions becuse the discriminant is less than zero.

3 0
3 years ago
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statuscvo [17]

Answer:

(1, 0)

Step-by-step explanation:

Please write this as y^2 = 4x; the " ^ " indicates exponentiation.

The appropriate equation for a horizontal parabola that opens to the right is

y^2 = 4px

Here, we are told that  y^2 = 4x; this tells us that 4p = 4, and so p = 1.  

Again, this parabola is a horizontal one and it opens to the right.  p = 1 is the distance of the focus from the vertex, and in this case p = 1.  Thus, the focus is at (1, 0) (situated on the x-axis).

6 0
3 years ago
I need help in geometry!
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Answer:

180-30

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