Answer:
Step-by-step explanation:-7/2
is the answer
Answer:
The period of Y increases by a factor of with respect to the period of X
Step-by-step explanation:
The equation shows the relationship between the orbital period of a planet, T, and the average distance from the planet to the sun, A, in astronomical units, AU. If planet Y is k times the average distance from the sun as planet X, at what factor does the orbital period increase?
For the planet Y:
For planet X:
To know the factor of aumeto we compared with
We know that the distance "a" from planet Y is k times larger than the distance from planet X to the sun. So:
So
Then, the period of Y increases by a factor of with respect to the period of X
<span>The correct answer is it must be a right angle.
Explanation<span>:
This is a rhombus, as it is a parallelogram with all congruent sides. In a rhombus, diagonals are perpendicular bisectors of each other; this means that they meet at right angles, so MSR must be a right angle.</span></span>
Answer:
66 pots
Step-by-step explanation: