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GalinKa [24]
3 years ago
11

Find the value of y for the given value of x.

Mathematics
2 answers:
Gnesinka [82]3 years ago
8 0
Y = 7x ; x = -5

Y = 2

Y = x2 + 9 ; x = - 12

Y = -15

Sorry if it’s incorrect
tia_tia [17]3 years ago
5 0
X=30 in the first one and x=-15 in the second one
You might be interested in
U divided by 25 =13 please do step by step and show work thanks :))
Anna71 [15]
Answer U/25=13
             U=13 divided 1/25
             U=13 multiply 25
             U=325
6 0
3 years ago
Solve : <br> 20-9x=11<br> 4(2x+1)=8<br> 5(2x+5)=-15<br> 3(8x+1)=-21
laila [671]
<span>20-9x=11
-9x=11-20
-9x= -9
x= -9/(-9)
x=1


4(2x+1)=8
2x+1=8/4
2x+1=2
2x=2-1
2x=1
x=1/2
x=0.5


5(2x+5)=-15
2x+5= -15/5
2x+5= -3
2x= -3-5
2x= -8
x= -8/2
x=-4

3(8x+1)=-21
8x+1= -21/3
8x+1= -7
8x= -7-1
8x =-8
x= -8/8
x= -1
</span>
4 0
3 years ago
Rewrite in simplest terms: 4(-5u +3) – 4(8u - 1)
viktelen [127]

Answer:

You distribute then combine

your answer is <u><em>-52u+16</em></u>

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
The slope of the line below is -1/7. Write a point-slope equation of the line using the coordinates of the labeled point ( 3, 3)
Varvara68 [4.7K]
Y - 3 = -1/7(x - 3)

answer is B.

hope it helps
8 0
3 years ago
If IQ scores are normally distributed with a mean of 100 and a standard deviation of 5, what is the probability that a person se
notsponge [240]

Answer:

2.28% probability that a person selected at random will have an IQ of 110 or higher

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 100, \sigma = 5

What is the probability that a person selected at random will have an IQ of 110 or higher?

This is 1 subtracted by the pvalue of Z when X = 110. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{110 - 100}{5}

Z = 2

Z = 2 has a pvalue of 0.0228

2.28% probability that a person selected at random will have an IQ of 110 or higher

5 0
3 years ago
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