A because the line of symmetry is where the two parts of the image will meet
For a better understanding of the solution provided here, please find the diagram attached.
In the diagram, ABCD is the room.
AC is the diagonal whose length is 18.79 inches.
The length of wall AB is 17 inches.
From the given information, we have to determine the length of the BC, which is depicted a 
, because for the room to be a square, the length of the wall AB must be equal to the length of the wall BC.
In order to determine the length of the wall BC, or , we will have to employ the Pythagoras' Theorem here. Thus:
Thus, 
inches
and hence, the given room is not a square.
Answer:
18 and 9
OR
-18 and -9
Step-by-step explanation:
Let:
first number = x
second number = y
According to given conditions:
x - y = 9 ---------- eq1
x * y = 162 ------- eq2
From eq1:
x = 9 + y
Put it in eq2:
(9+ y)*y = 162
9y + y^2 - 162 = 0
OR
y^2 + 9y -162 = 0
By factorizing we get:
y^2 -9y + 18y - 162 = 0
Taking common:
y(y - 9) + 18(y - 9) = 0
(y - 9)(y + 18) = 0
So:
y = -18 and y = 9
ignoring negative integer
Putting values of y in eq1:
x - 9 = 9
x = 9 + 9
x = 18
So the two numbers are:
18 and 9
OR
-18 and -9
i hope it will help you!
Answer:
x = 3
Step-by-step explanation:
We need it in factorized form to get x.
If the quadratic equation can be divided by a-2 the first part is:
(a-2)
Now to get a², the a must be multpilied by itself. So
(a-2)(a)
To get -10, -2 must be multiplied by 5. So:
(a-2)(a+5)
we can expand to get x
a² + 5a - 2a -10
a² + 3a - 10
a² + ax - 10
x = 3
Answer:
659
Step-by-step explanation:
