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Vladimir [108]
3 years ago
7

Inequality of t+250+800

Mathematics
1 answer:
rosijanka [135]3 years ago
7 0

Answer:

2983839i8

468393749493948

Hsjejrhrjjh4u4i84748394

Je83847483

373783838383884

373838383

Jkffffffffffffffffffffffffffffdddfddfffffffddddddddddddddddddfffffffffffffffffffffffffff

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I have the formula <br><br> A fraction • π r^2
MatroZZZ [7]

Answer:

22.2 ft²

Step-by-step explanation:

The area (A) of a sector is calculated as

A = area of circle × fraction of circle

  = πr² × \frac{50}{360}

  = π × 7.13² × \frac{5}{36}

  = \frac{7.13^2(5)\pi }{36} ≈ 22.2 ft² ( nearest tenth )

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Use distributive property and area models to solve these equations . Show your work. 4 x 9.4 6.4 x 1.2 3.5 x 4.9 8.4 x 5.2
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The Awnser is 9.4 6.4
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An equilateral triangle is always __________. A. obtuse and isosceles B. acute and isosceles C. scalene D. obtuse
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For the given hypothesis test, determine the probability of a Type II error or the power, as specified. A hypothesis test is to
erica [24]

Answer:

the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

Step-by-step explanation:

Given the data in the question;

we know that a type 11 error occur when a null hypothesis is false and we fail to reject it.

as in it in the question;

obtained mean is 9.8 which is obviously not equal to 8.3

But still we fail to reject the null hypothesis says mean is 8.3

Hence we have to find the probability of type 11 error

given that; it is right tailed and o.5, it corresponds to 1.645

so

z is equal to 1.645

z = (x-μ)/\frac{S}{\sqrt{n} }

where our standard deviation s = 3.8

sample size n = 50

mean μ = 8.3

we substitute

1.645 = (x - 8.3)/\frac{3.8}{\sqrt{50} }

1.645 = (x - 8.3) / 0.5374

0.884023 = x - 8.3

x = 0.884023 + 8.3

x = 9.18402

so, by general rule we will fail to reject the null hypothesis when we will get the z value less than 1.645

As we reject the null hypothesis for right tailed test when the obtained test statistics is greater than the critical value

so, we will fail to reject the null hypothesis as long as we get the sample mean less than 9.18402

Now, for mean 9.8 and standard deviation 3.8 and sample size 50

Z =  (9.18402 - 9.8)/\frac{3.8}{\sqrt{50} }

Z = -0.61598 / 0.5374

Z = - 1.1462 ≈ - 1.15

from the z-score table;

P(z<-1.15) = 0.1251

Therefore, the probability of a Type II error if in fact the mean waiting time u, is 9.8 minutes is 0.1251

Option A) is the correct answer.

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3 years ago
Consider the functions F and G in the tables below<br> PLEASE HELP PLEASE
d1i1m1o1n [39]

Answer:

Option A, As x increases, the rate of change exceeds the rate of f

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