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VARVARA [1.3K]
3 years ago
7

How much money was originally in an account if the balance is 10,399.86 if the interest compounded quarterly over eight years?

Mathematics
1 answer:
nlexa [21]3 years ago
5 0
Sorry I’m not sure but maybe you could look it up???
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Does choosing a blue marble represent the complement event of choosing a red marble? Explain.
Arada [10]

Answer:

Below is the sample response

Step-by-step explanation:

The complementary event for choosing a red marble is choosing a blue or purple. The total number of marbles is 5. The probability of choosing a red marble is 1/5, and the complement would be 4/5. That is not the same as choosing a blue marble.

3 0
3 years ago
Read 3 more answers
At the dog park, there are several dogs with their owners. Counting heads, there are 20; counting legs, there are 62. How many d
Nataly_w [17]
There are 9 owners and 11 dogs
9×2=18
11×4=44
44+18=62
6 0
3 years ago
PLEASE HELP FAST ...A museum surveyed three groups of 5 members to find out how many times the members visited the zoo in the pa
Sauron [17]
I think the group 2 survey is likely to be biased towards people who are not too keen on zoos since all the values are small.
From group 1 and 3 the mean number of visits are
     (4 + 10 + 6 + 3 + 8 + 7 + 9 + 3 + 4 + 7) / 10 

=   61/10

mean = 6
6 0
3 years ago
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Ramona had eight and three eighths inches of ribbon. She used two and a half inches for an art project. How many inches of ribbo
IceJOKER [234]
-8 3/8 - 2 1/2 = 67/8 - 5/2 = 67/8 - 20/8 = 47/8 also = to 5 7/8
67 - 20 =47
answer: 5 7/8

3 0
3 years ago
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A test taker gets 70 on 1st exam, 80 on 2nd exam, 2/3 of 4/5 of his 2nd exam on his 3rd test. If the professor gives 5 points ex
Serga [27]
<h3>Answer:  127</h3>

=================================================

Explanation:

The phrasing "2/3 of 4/5 of his 2nd exam on his 3rd test" is a bit clunky in my opinion. It seems more complicated than it has to be.

The student got 80 on the second exam. 4/5 of this is (4/5)*80 = 0.8*80 = 64. Then we take 2/3 of this to get (2/3)*64 = 42.667 approximately. If we assume only whole number scores are given, then this would round to 43.

Let x be the score on the fourth exam. Since 5 points of extra credit are given, the student actually got x+5 points on this exam.

So we have these scores

  • first exam = 70
  • second exam = 80
  • third exam = 43
  • fourth exam = x+5

Adding up these scores and dividing by 4 will get us the average

(sum of scores)/(number of scores) = average

(70+80+43+x+5)/4 = 80

(x+198)/4 = 80

x+198 = 4*80

x+198 = 320

x = 320 - 198

x = 122

So the student got a score of x+5 = 122+5 = 127 on the fourth exam.

7 0
3 years ago
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