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2 years ago

A rental car company charges $31 per day to rent a car and $0.13 for every mile

Mathematics

1 answer:

lord [1]2 years ago

8 0

Answer:

The number of days is at most 5 days

= d ≤ 5 days

Step-by-step explanation:

A rental car company charges $31 per day to rent a car and $0.13 for every mile driven. Jocelyn wants to rent a car, knowing that:

She plans to drive 500 miles.

• She has at most $220 to spend.

At most means Less than or equal to $220

The inequality for expressing this = ≤

Hence, the inequality which can be used to determine d, the number of days Jocelyn can afford to rent while staying within her budget.

$31 × d + $0.13 × 500 miles ≤ $200

The inequality is given as:

31d + 65 ≤ 220

Solving further

31d ≤ 220 -65

31d ≤ 155

d ≤ 155/31

d ≤ 5

Therefore, the number of days is at most 5 days

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3 years ago

In a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of th

11111nata11111 [884]

Answer:

Required probability is 0.784 .

Step-by-step explanation:

We are given that in a large statistics course, 74% of the students passed the first exam, 72% of the students pass the second exam, and 58% of the students passed both exams.

Let Probability that the students passed the first exam = P(F) = 0.74

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Probability that the students passed both exams = $P(F \bigcap S)$ = 0.58

Now, if the student passed the first exam, probability that he passed the second exam is given by the conditional probability of P(S/F) ;

As we know that conditional probability, P(A/B) = $\frac{P(A\bigcap B)}{P(B) }$

Similarly, P(S/F) = $\frac{P(S\bigcap F)}{P(F) }$ = $\frac{P(F\bigcap S)}{P(F) }$ {As $P(F \bigcap S)$ is same as $P(S \bigcap F)$ }

= $\frac{0.58}{0.74}$ = 0.784

Therefore, probability that he passed the second exam is 0.784 .

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3 years ago

What are the solution(s) to the quadratic equation 9x2 = 4?

Kaylis [27]

Answer:

Option B.

Step-by-step explanation:

The given quadratic equation is

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We need to find the solution of given quadratic equation.

Divide both sides by 9.

$\frac{9x^2}{9}=\frac{4}{9}$

$x^2=\frac{4}{9}$

Taking square root on both sides.

$x=\pm\sqrt{\frac{4}{9}}$

$x=\pm\frac{2}{3}$

The solution of given equation are $x=\frac{2}{3}$ and $x=-\frac{2}{3}$ .

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3 years ago

Read 2 more answers

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3 years ago

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