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anastassius [24]
3 years ago
5

15) will mark BRAINLIEST AND 10 POINTS.

Mathematics
2 answers:
vaieri [72.5K]3 years ago
6 0
Equation identically true
Ksivusya [100]3 years ago
6 0
Cotx=cosx/sinx
cot²x=cos²x/sin²x
cscx=1/sinx, cscx+1=1/sinx +sinx/sinx=(1+sinx)/sinx

cot²x/(cscx+1)=(cos²x/sin²x)*(sinx/(1+sinx)=cos²x/[sinx(1+sinx)]

Recall that sin²x+cos²x=1, so cos²x=1-sin²x=(1+sinx)(1-sinx)

therefore: cos²x/[sinx(1+sinx)] can be written as
(1+sinx)(1-sinx)//[sinx(1+sinx)]=(1-sinx)/sinx=the left side.

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2x-y=-1 in slope intercept form
Anvisha [2.4K]

Answer:y=2x+1

I believe. I could be wrong. But I think im right

Step-by-step explanation:

2x-y=-1

-2x -2x

(-1)-y=-1-2x(-1)

y=2x+1

5 0
3 years ago
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Help ASAP!!! Please show all work!!!!!!!
Anastaziya [24]

Answer:

x = 2 and x = -3

Step-by-step explanation:

We need to find the value of x in the below expression.

\sqrt{x+7} -1=x

Adding 1 to both sides,

\sqrt{x+7} -1+1=x+1\\\\\sqrt{x+7}=x+1

Squaring both sides,

x+7=(x+1)^2\\\\x+7=x^2+1+2x\\\\x^2+1+2x-x-7=0\\\\x^2+x-6=0\\\\x=2\ and\ -3

Hence, this is the required solution.

6 0
3 years ago
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Y=6x^2-12x-1 minumim function value
ch4aika [34]

Answer:

(−1,5)

Step-by-step explanation:

hope this helpes

3 0
2 years ago
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Match each function with its domain.
kari74 [83]

What you meant was range. The range scales from top to bottom. You can know this by graphing and practicing memorizing these function's domain and range.

Function:                  Range:

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p(x) = ∛2-x          All real numbers

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r(x) = -2 + √2-x          y ≥ -2

k(x) = 2 - √x               y ≤ 2

v(x) = √-x                   y ≥ 0

8 0
3 years ago
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If the discriminant of a quadratic equation is -8, which statement describes the roots
SVETLANKA909090 [29]

There are no statements on your list that describe the roots.

If the discriminant is a negative number, then the two roots
of the equation are complex conjugates.  They both have
imaginary parts to them.

8 0
3 years ago
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