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SIZIF [17.4K]
3 years ago
5

What is X and how do I find it?

Mathematics
2 answers:
worty [1.4K]3 years ago
5 0

Answer:

X = 33.05

Step-by-step explanation:

\sin(x)  =   \frac{6}{11}   \\ x = 33.05

andrew11 [14]3 years ago
4 0

Answer:

x = 33 ( rounded to the nearest whole )

x = 33.1 ( rounded to the nearest tenth )

x = 33.06 ( rounded to the nearest hundredth )

Step-by-step explanation:

We can solve for x using trigonometry

Remember these are the "common" trig ratios

Sin = Opposite over Hypotenuse

Cos = Adjacent over Hypotenuse

Tan = Opposite over Adjacent

For angle "x" we are given it's opposite side length (6) and the hypotenuse (11)

When working with the opposite side length and hypotenuse we use trig ratio Sine.

Recall that sin = opposite over hypotenuse

Thus, sin(x)=\frac{6}{11}

We then want to isolate "x"

To do so we need to get rid of the "sin"

We can do this by multiplying each side by the inverse of sin ( sin ) ^-1

sin(x)*sin^-^1=x\\sin^-^1(\frac{6}{11}) =33.05573115

we're left with x = 33.05573115

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Furkat [3]

Answer:

D) 2, 4, 8, 16, 32

Step-by-step explanation:

We have given four sets of sequence.

And we have to find out which sequence is not an arithmetic sequence.

For this the given sequences should satisfy the value of common difference(d) and Arithmetic Progression formula.

A.P. Formula,

T_n=a+(n-1)d

Where T_n = nth term of an A.P.

a = first term of an A.P.

n = number of terms.

d = common difference.

'd' is calculated by subtracting fist term from second term.

d = second\ term-first\ term

A) 4, 7, 10, 13, 16

d = 7-4=3

d = 10-7=3

Here d=3 and 5th term is 16.

So we find out the 5th term by using the formula of A.P. To check whether the sequence is in A.P. or not.

T_5=4+(5-1)3=4+4\times\ 3=4+12=16

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

B) 1, 2, 3, 4, 5

d =2-1=1

d =3-2=1

Here d=1 and 5th term is 5.

T_5=1+(5-1)1=1+4=5

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

C) 15, 9, 3, -3, -9

d =9-15=-6

d =3-9=-6

Here d=-6 and 5th term is -9.

T_5=15+(5-1)-6=15+4\times -6=15+(-24)=-9

Here the given sequence fulfills the condition of being in A.P.

Hence the given sequence is an arithmetic sequence.

D) 2, 4, 8, 16, 32

d_1=4-2=2

d_2=8-4=4

Here d_1=2\ But\ d_2=4

The common difference between the terms is not same.

In case of d_1.

T_5=2+(5-1)2=2+4\times 2=2+8=10

In case of d_2.

T_5=2+(5-1)4=2+4\times 4=2+16=18

Here the given sequence does not fulfills the condition of being in A.P.

Hence the given sequence is not an arithmetic sequence.

Hence the correct option is D) 2, 4, 8, 16, 32.

4 0
4 years ago
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