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3 years ago

5

Help me answer this please

1 answer:

Diano4ka-milaya [45]3 years ago

3 0

The standard form for linear equations in two variables is Ax+By=C. For example, 2x+3y=5 is a linear equation in standard form. When an equation is given in this form, it's pretty easy to find both intercepts (x and y). This form is also very useful when solving systems of two linear equations.

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Find the root that is a real number. rootindex 4 startroot 4096 endroot

Sati [7]

The answer would be C.

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3 years ago

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What is the greatest common factor of 36 and 90?

s344n2d4d5 [400]

Answer:

18

Step-by-step explanation:

The greatest common factor is 18. All of the common factors are: 1, 2, 3, 6, 9, 18.

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3 years ago

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Please help. Will reward brainliest

algol13

Answer:

Ok then the answer is B

3 0

3 years ago

¿En cuánto se convierte un capital de C=$8,000 después de n=5 años a una tasa de interés compuesto del i=10% anual?

slava [35]

Evaluando una ecuación exponencial, veremos que luego de 5 años el capital se convierte en $12,884.08

<h3>¿En cuánto se convierte el capital?</h3>

Esta situación se podra modelar con la ecuación exponencial:

f(n) = $8,000*(1 + 10%/100%)ⁿ

Donde n es el número de años.

Podemos simplificar la ecuación para obtener:

f(n) = $8,000*(1.1)ⁿ

Ahora queremos ver el valor que toma esto cuando n = 5, asi obtenemos:

f(n) = $8,000*(1.1)⁵ = $12,884.08

Así que luego de 5 años, el capital se convierte en $12,884.08.

Sí quieres aprender más sobre ecuaciones exponenciales:

brainly.com/question/11832081

#SPJ1

4 0

2 years ago

Total freshman = 58. Number of freshman who prefer cheese toppings= 14. Determined the probability that a freshman prefer cheese

Yakvenalex [24]

Answer:

The probability that a freshman prefer cheese toppings is 0.241

Step-by-step explanation:

Probability of any event E = $\frac{\textrm{Number of favorable outcomes}}{\textrm{Total number of outcomes}}$

Here, let E : Event of choosing cheese toppings

So, the number of favorable outcomes = 14

Total number of outcomes = 58

So, $P(E) = \frac{\textrm{Number of students who like cheese toppings}}{\textrm{Total number of students}}$

or, P(E) = $\frac{14}{58} = 0.241379$

So,the probability that a freshman prefer cheese toppings is 0.241379

Rounding of 0.241379 to the <u>nearest thousandth</u>, we get

Here , in 0.241379 thousandth digit is 3, and 3 < 5,

so the value of P(E) = 0.241

4 0

3 years ago