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Komok [63]
3 years ago
9

When drawing a free body diagram, which of the following things would NOT be included

Physics
1 answer:
Neko [114]3 years ago
5 0
C. Mass of the object
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An airplane starts from rest and reaches a takeoff velocity of 60.0m/s due north in 4.0s. How far has it traveled before take of
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Initial velocity, u = 0
Final velocity, v = 60 m/s  (at take off)
Duration of the acceleration, t = 4 s

Calculate average acceleration.
a = (v - u)/t
   = (60 m/s)/(4 s)
   = 15 m/s²

Calculate the distance traveled during acceleration.
s = ut + (1/2)*a*t²
   = 0.5*(15 m/s²)*(4 s)²
   = 120 m

Answer: 120 m

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In space, astronauts use an electrical medium to talk to each other... Why??<br><br>​
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it can be transmited extremely fast

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3 years ago
hurriquake nails help homes better withstand the damages of both earthquakes and hurricanes. the cause is largely because the la
NeTakaya

If the nails dimensions were expressed in meters, we would have to divide it by 100.

In earlier times there were 3 main types of measurement systems:

1.The CGS system(centimetre, gram and second)

2.• The FPS system( foot, pound and second)

3.• The MKS system(metre, kilogram and second)

But in the present day, we use Système Internationale d’ Unites (French for International System of Units), abbreviated as SI.

The SI Unit of length is meter, but in many cases the length is given in centimeters.

So, we have to convert the value given in centimeter to meter by using the conversion factor which is,

1 meter = 100 centimeters

1 cm = 1/100 meter

Therefore, if the nails dimensions were expressed in meters, we would have to divide it by 100.

To know more about "SI Units", refer to the following link:

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6 0
2 years ago
15. यदि दिइएको केन्द्र 0 भएको वृत्तको
miv72 [106K]

Answer:

what language is that

Explanation:

i don't understand the languge u used please can you change it

8 0
3 years ago
While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at th
fiasKO [112]

Answer:

Option A is correct - While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at that point. The lowest-frequency standing wave that could be present on the string vibrates at twice the fundamental frequency.

Explanation:

Before touching the midpoint of the string, the string vibrates with one loop.

Fundamental frequency, f1 = v/(2*L)

Now, when the midpoint of the guitar string was touched, the string vibrates with two loops.

Hence, f2 = 2*v/(2*L)

f2 = 2*f1

Therefore, compared to the fundamental frequency the frequency would be double.

Option A is correct - While a guitar string is vibrating, you gently touch the midpoint of the string to ensure that the string does not vibrate at that point. The lowest-frequency standing wave that could be present on the string vibrates at twice the fundamental frequency.

4 0
3 years ago
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