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1 year ago

A cube of side 0.2 m rests on the floor as shown.

Physics

1 answer:

andrey2020 [161]1 year ago

4 0

Pressure= hqg
H=depth
q=density
g=gravity

h=0.2
q=7
g=10

0.2*7*10= 14pa

FINAL ANSWER = 14pa

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The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee

lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is $-27.3\hat{i}$

y component of vector is $43.6\hat{j}$

so position vector is

$r=-27.3\hat{i}+43.6\hat{j}$

Magnitude of vector is

$|r|=\sqrt{27.3^2+43.6^2}$

$|r|=\sqrt{2646.25}$

|r|=51.44 units

Direction

$tan\theta =\frac{43.6}{-27.3}=-1.597$

vector is in 2nd quadrant thus

$180-\theta =57.94$

$\theta =122.06^{\circ}$

4 0

3 years ago

Write the formula of mechanical advantage

Zanzabum

Answer:

the formula of mechanical advantage is

MA = load / effort

VR = effort distance / load distance

hope it is helpful to you

7 0

2 years ago

Part A What will be the equilibrium temperature when a 227 g block of copper at 283 °C is placed in a 155 g aluminum calorimeter

stellarik [79]

Answer:

T = 20.84°C

Explanation:

From the law of conservation of energy:

Heat Lost by Copper Block = Heat Gained by Aluminum Calorimeter + Heat Gained by Water

$m_cC_c\Delta T_c = m_wC_w\Delta T_w + m_aC_a\Delta T_a$

where,

$m_c$ = mass of copper = 227 g

$m_w$ = mass of water = 844 g

$m_a$ = mass of aluminum = 155 g

$C_c$ = specific heat capacity of calorimeter = 385 J/kg.°C

$C_w$ = specific heat capacity of water = 4200 J/kg.°C

$C_a$ = specific heat capacity of aluminum = 890 J/kg.°C

$\Delta T_c$ = change in temperature of copper = 283°C - T

$\Delta T_w$ = change in temperature of water = T - 14.6°C

$\Delta T_a$ = change in temperature of aluminum = T - 14.6°C

T = equilibrium temperature = ?

Therefore,

$(227\ g)(385\ J/kg.^oC)(283^oC-T)=(844\ g)(4200\ J/kg.^oC)(T-14.6^oC)+(155\ g)(890\ J/kg.^oC)(T-14.6^oC)\\\\24732785\ J - (87395\ J/^oC) T = (3544800\ J/^oC) T - 51754080\ J+ (137950\ J/^oC) T-2014070\ J\\\\24732785\ J +51754080\ J+2014070\ J = (3544800\ J/^oC) T+(137950\ J/^oC+(87395\ J/^oC) T\\\\78560935\ J = (3770145\ J/^oC) T\\\\T = \frac{78560935\ J}{3770145\ J/^oC}$

T = 20.84°C

8 0

2 years ago

A consequence of more mass having more inertia is that _____ is required to bring the helicopter to the same speed as the bullet

____ [38]

Answer:

The answer to your question is more force

Explanation:

A consequence of more mass having more inertia is that more force is required to bring the helicopter to the same speed as the bullet

I hope this helps and have a good day!

7 0

1 year ago

Calculate the normal force pushing up from the table in each example 8 kg

garik1379 [7]

The correct answer to the question is: 78.4 N.

EXPLANATION:

As per the question, the mass of the object is given as m = 8 Kg.

We are asked to calculate the normal force of the object.

The object is resting on the table.

Hence, the object pushes the table downward with a force equal to it's weight.

The table, in turn, pushes the object with the same force as given by the object, but in the upward direction.

The force given by the table on the object is known as the normal reaction of the object which acts perpendicular to the surface of the object.

Hence, the normal reaction is equal to the weight of the body.

The weight of a body is the product of it's mass with acceleration due to gravity.

So, the weight of 8 Kg object is calculated as -

Weight = mg

= 8 × 9.8 N.

= 78.4 N.

Here, g is known as acceleration due to gravity.

Hence, the normal force pushing up from the table is 78.4 N.

8 0

2 years ago