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3 years ago

An engineer is investigating potential energy with two

Physics

2 answers:

miv72 [106K]3 years ago

4 0

Answer:

Since they move in the same direction, share the same magnetic qualities, and move one unit identically
We can safely say its D

nadya68 [22]3 years ago

4 0

I would also say D because that looks like it would be the best logical guess from what I see.

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A selective college usually requires more years of _____ than a high school requires.

ipn [44]

Answer:

World languages__

Explanation:

A selective college usually requires more years of ___World languages__ than a high school requires. College graduates would look for jobs after college, they might have to travel to different countries. So, educating them about different language would give them a competitive edge to them. Moreover, in the age of globally integrated business community, knowing an extra language could work as cherry top on the cake.

5 0

3 years ago

using newtons law a force of 250N is applied to an object that accelerates at a rate of 5M/s2 what is the mass of the object?

AURORKA [14]

Answer:

50 kg

Explanation:

F = ma

250 N = m (5 m/s²)

m = 50 kg

7 0

3 years ago

It takes a car 1.75 h to go from mile marker 115 what's the average speed of the car?

emmainna [20.7K]

The average speed of the car is

(the mile marker he passes at the end of the 1.75 h) minus 115
divided by
(1.75 hours) .

The unit is 'miles per hour'.

6 0

3 years ago

A 4 cm diameter "bobber" with a mass of 3 grams floats on a pond. A thin, light fishing line is tied to the bottom of the bobber

Tasya [4]

Answer:

Explanation:

Calculate the volume of the lead

$V=\frac{m}{d}\\\\=\frac{10g}{11.3g'cm^3}$

Now calculate the bouyant force acting on the lead

$F_L = Vpg$

$F_L=(\frac{10g}{11.3g/cm^3} )(1g/cm^3)(9.8m/s^2)\\\\=8.673\times 10^{-3}N$

This force will act in upward direction

Gravitational force on the lead due to its mass will act in downward direction

Hence the difference of this two force

$T=mg-F_L\\\\=(10\times10^{-3}kg(9.8m/s^2)-8.673\times 10^{-3}\\\\=8.933\times10^{-3}N$

If V is the volume submerged in the water then bouyant force on the bobber is

$F_B=V'pg$

Equate bouyant force with the tension and gravitational force

$F_B=T_mg\\\\V'pg=\frac{(8.933\times10^{-2}N)+mg}{pg} \\\\V'=\frac{(8.933\times10^{-2}N)+mg}{pg}$

Now Total volume of bobble is

$\frac{V'}{V^B} =\frac{\frac{(8.933\times10^{-2})+Mg}{pg} }{\frac{4}{3} \pi R^3 }\times100\\\\=\frac{\frac{(8.933\times10^{-2})+(3)(9.8)}{(1000)(9.8)} }{\frac{4}{3} \pi (4.0\times10^{-2})^3 }\times100\\\\$