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3 years ago

HELP!!!

Mathematics

2 answers:

Mandarinka [93]3 years ago

7 0

15.5 hours is the answer

Pavlova-9 [17]3 years ago

6 0

Answer:

i need help with this please help me Explain why the crossbreeding of bison and cattle is both a benefit and hindrance to conservation efforts aimed at protecting bison genetic diversity.

Step-by-step explanation:

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I need help asapppppppppp<br> AB=14

dedylja [7]

Answer:

14π

Step-by-step explanation:

The equation for circumference is

C = π* diameter

AB is the diameter, so the circumference is 14π

8 0

3 years ago

I need to know what the answer is and how to solve it

natka813 [3]

I put the ... because it just keeps on going. Just round it to 8.

6 0

2 years ago

Veronica says that the expression

ELEN [110]

The person on top is correct

6 0

2 years ago

A quantity with an initial value of 6200 decays continuously at a rate of 5.5% per month. What is the value of the quantity afte

ELEN [110]

Answer:

410.32

Step-by-step explanation:

Given that the initial quantity, Q= 6200

Decay rate, r = 5.5% per month

So, the value of quantity after 1 month, $q_1 = Q- r \times Q$

$q_1 = Q(1-r)\cdots(i)$

The value of quantity after 2 months, $q_2 = q_1- r \times q_1$

$q_2 = q_1(1-r)$

From equation (i)

$q_2=Q(1-r)(1-r) \\\\q_2=Q(1-r)^2\cdots(ii)$

The value of quantity after 3 months, $q_3 = q_2- r \times q_2$

$q_3 = q_2(1-r)$

From equation (ii)

$q_3=Q(1-r)^2(1-r)$

$q_3=Q(1-r)^3$

Similarly, the value of quantity after n months,

$q_n= Q(1- r)^n$

As 4 years = 48 months, so puttion n=48 to get the value of quantity after 4 years, we have,

$q_{48}=Q(1-r)^{48}$

Putting Q=6200 and r=5.5%=0.055, we have

$q_{48}=6200(1-0.055)^{48} \\\\q_{48}=410.32$

Hence, the value of quantity after 4 years is 410.32.

4 0

2 years ago

Read 2 more answers

2−6(−5t+1)

VashaNatasha [74]

Answer: I don't think any of those choices are correct.

Step-by-step explanation:

2-6*-5t+6

6*-5t+4

6 0

3 years ago

Read 2 more answers