Answer:
<h3>
(2, 124)</h3>
Step-by-step explanation:
f(x) = a(x - h)² + k - the vertex form of the equation of the parabola with vertex (h, k)
![f(x) = -16x^2+ 64x + 80\\\\f(x) = -16(x^2- 4x) + 80\\\\f(x) = -16(\underline {x^2-2\cdot2x\cdot2+2^2}-2^2) + 80\\\\f(x) = -16\big[(x-2)^2-4\big] + 80\\\\f(x) = -16(x-2)^2+64 + 80\\\\\bold{f(x)=-16(x-2)^2+124\quad\implies\quad h=2\,,\quad k=124}](https://tex.z-dn.net/?f=f%28x%29%20%3D%20-16x%5E2%2B%2064x%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28x%5E2-%204x%29%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28%5Cunderline%20%7Bx%5E2-2%5Ccdot2x%5Ccdot2%2B2%5E2%7D-2%5E2%29%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%5Cbig%5B%28x-2%29%5E2-4%5Cbig%5D%20%2B%2080%5C%5C%5C%5Cf%28x%29%20%3D%20-16%28x-2%29%5E2%2B64%20%2B%2080%5C%5C%5C%5C%5Cbold%7Bf%28x%29%3D-16%28x-2%29%5E2%2B124%5Cquad%5Cimplies%5Cquad%20h%3D2%5C%2C%2C%5Cquad%20k%3D124%7D)
<u>The vertex is </u><u>(2, 124)</u>
angles EFH and GFH are congruents
for the second equivalence criterion two triangles are equivalents if they have respectively 2 angles and 1 side congruents
the two triangles have congruents the angle right angle (HGF and HEF) and the 55 degrees angles (EFH and GFH); then they have in common the HF side.
so the triangles are congruent and so all the sides are respectively congruent,for example EH with HG:
EH=HG
s+36=7s
s+36-7s=0
s-7s=-36
-6s=-36
6s=36
s=6
<em>sorry for my english</em>
We did this this year and by what I can remember I belive it is 4,320 inches. I hope this helps and I hope I got it right so u don't get it wrong.
Answer:
infinite number of solutions
Step-by-step explanation:
Work with the second equation. Subtract 8x from both sides.
- 4y + 8x - 8x = -8x - 12 Collect like terms.
-4y = - 8x - 12 Divide by - 4
-4y/-4 = - 8x/-4 - 12/-4
y = 2x + 3
That is exactly the same line as the first given. There is an infinite number of solutions.
