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In a class, every student knows French or German (or both). 15 students know French, and 17 students know German.

Nikolay [14]

You would do 15 + 17. Which equals 32, and that is the least, then choose a number that is larger than 32.

5 0

3 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

4 0

3 years ago

Investments historically have doubled every 9 years. if you start with 2,000 investment, how much money would you have after 45

77julia77 [94]

Answer: 64,000

Equation: 2,000*2^(45/9)

4 0

2 years ago

6. A hospital needs a supply of an expensive medicine. Company A has the most

Anton [14]

We are required to find the total milligrams if medicine the hospital can get from the three companies.

The total quantity of medicine the hospital can get from the three companies is 2.75 milligrams

There are there companies:

Company A

Company B

Company C

Company A = 1.3 milligrams

Company A is 0.9 milligrams more than Company C's

A = 0.9 + C

1.3 = 0.9 + C

1.3 - 0.9 = C

0.4 = C

C = 0.4 milligrams

Company A is also twice the difference between the weight of

Company B's supply and Company C's

A = 2(B - C)

1.3 = 2(B - 0.4)

1.3 = 2B - 0.8

1.3 + 0.8 = 2B

2.1 = 2B

Divide both sides by 2

B = 2.1/2

B = 1.05 milligrams

Therefore,

A + B + C

= 1.3 + 1.05 + 0.4

= 2.75 milligrams