Well, let's see . . . . .
2, 4, and 48
2, 6, and 46
2, 8, and 44
2, 10, and 42
2, 12, and 40
2, 14, and 38
2, 16, and 36
2, 18, and 34
.
.
and so on and so forth.
When I keep going and do all of them, I get 46 answers altogether.
If you need the even numbers to be consecutive,
then they're 16, 18, and 20 .
They have a comma in front of the third number for example, 12,345 there is a in front of this third number
Answer:
No, This is not a valid Probability Distribution
Step-by-step explanation:
Probability [Neighbour walks with Beagle] = 20%
Probability [Neighbour walks with Golden Retriever] = 70%
Probability [Neighbour walks alone] = 30%
Disjoint Events are the events that have zero probability of occurring together. If all the three above items are disjoint, it means that it can never happen that two of them happen together.
The total (summed) probability of a valid probability distribution, with disjoint sets = 1 . In given case, total probability = 0.2 + 0.7 + 0.3 = 1.2 ; i.e > 1.
So, this probability distribution with stated disjoint events is not a Valid Probability distribution.
A) n-20
b.)30=1/2n+1/2
c.)2/3n=30
d.)5n=90
e.)M•3+4=49