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SpyIntel [72]
3 years ago
8

The diameter of a circle has endpoints (2,-6) and (-4,-16).

Mathematics
1 answer:
olga nikolaevna [1]3 years ago
3 0

Answer:

(x + 1)^{2}  + (y + 11)^{2} = 34

Step-by-step explanation:

First find the midpoint of the segment  from (2, -6) to (-4, -16)

((2 - 4)/2, (-6 - 16)/2)

(-2/2, -22/2)

(-1, -11) is the midpoint and is the center of the circle

Now find the distance between the 2 given points and divide by 2 to get the radius of the circle

d = \sqrt{(2 + 4)^{2} + (-6 + 16)^{2}  }

  = \sqrt{6^{2} + 10^{2}  }

  = \sqrt{36 + 100}

  = \sqrt{136}

r = \sqrt{136}/2

r^{2} = 136/4 = 34

Equation of circle with center at (-1, -11) and radius = \sqrt{34} is

(x + 1)^{2}  + (y + 11)^{2} = 34

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Kitty [74]

Answer:

D(4,-3)

Step-by-step explanation:

Given three of the vertices of the square: A(4, -7), B(8, -7),C(8, -3)

Let the coordinate of the fourth vertex be D(x,y).

We know that diagonals of a square are perpendicular bisector. So, the midpoint of both diagonals is the same.

The diagonals are BD and AC

Midpoint of BD = Midpoint of AC

\left(\dfrac{8+x}{2},\dfrac{-7+y}{2}\right) =\left(\dfrac{4+8}{2},\dfrac{-7+(-3)}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(\dfrac{12}{2},\dfrac{-10}{2}\right)\\ \left(\dfrac{8+x}{2},\dfrac{y-7}{2}\right) =\left(6,-5\right)\\$Therefore$:\\\dfrac{8+x}{2}=6\\8+x=12\\x=12-8\\x=4\\$Similarly$\\\dfrac{y-7}{2}=-5\\y-7=-5*2\\y-7=-10\\y=-10+7=-3

The coordinates of the fourth vertex is D(4,-3)

3 0
3 years ago
Z+z+z for x=2, y=-3 , z=-4
REY [17]

Answer:

-12

Step-by-step explanation:

Just sustitute the z for -4

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I hope this help :)

5 0
3 years ago
Read 2 more answers
Verbal expression for seven to the 3rd power
miv72 [106K]
7^3 power is the answer to your question
4 0
3 years ago
I need these questions answered ASAP thx!!
Korvikt [17]

A) profit is 8$, the price increases 8$ every time or each pie is $4

B)N times 4= P

C) 15 times 4= $60 Profit. Because each pie is 4$

D) if 144$ are made and each pie is $4, you’d divide 144 by 4= 36. 36 Pies were sold.

I hope this is correct and helps :)

6 0
3 years ago
Find all point(s) of intersection of the line y = 4x and the parabola y = x^2 - 2x + 9.
Goshia [24]

Answer:

A) (3, 12)

Step-by-step explanation:

For such a problem, I like to use a graphing calculator. It shows the answer quickly without a lot of fuss.

_____

If you want to solve this analytically, set the difference in y-values equal to zero and solve the resulting quadratic in the usual way. This will give the x-value at which the y-values are equal. (After we find x, we still need to find y.)

... y - y = 0

... x² -2x +9 -4x = 0

... x² -6x +9 = 0 . . . . . . collect terms. Recognize this as a perfect square.

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... x = 3 is the solution to this

... y = 4x = 4·3 = 12

The point on each of the given curves is (x, y) = (3, 12). The line is tangent to the parabola there, so there is only one point of intersection.

6 0
3 years ago
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