Answer:
First image attached
The error was done in Step E, because student did not multiply
by the negative sign in numerator. Step E must be
.
Second image attached
The error was done in Step C, because the student omitted the
of the algebraic identity
. Step C must be ![5\cdot x = x^{2}+4\cdot x + 4](https://tex.z-dn.net/?f=5%5Ccdot%20x%20%3D%20x%5E%7B2%7D%2B4%5Ccdot%20x%20%2B%204)
Step-by-step explanation:
First image attached
The error was done in Step E, because student did not multiply
by the negative sign in numerator. The real numerator in Step E should be:
![3-(2\cdot x -8)= 3-2\cdot x+8 = 11-2\cdot x](https://tex.z-dn.net/?f=3-%282%5Ccdot%20x%20-8%29%3D%203-2%5Ccdot%20x%2B8%20%3D%2011-2%5Ccdot%20x)
Hence, Step E must be
.
Second image attached
The error was done in Step C, because the student omitted the
of the algebraic identity
. Step C must be ![5\cdot x = x^{2}+4\cdot x + 4](https://tex.z-dn.net/?f=5%5Ccdot%20x%20%3D%20x%5E%7B2%7D%2B4%5Ccdot%20x%20%2B%204)
And further steps are described below:
Step D
![x^{2}-x+4 = 0](https://tex.z-dn.net/?f=x%5E%7B2%7D-x%2B4%20%3D%200)
Which according to the Quadratic Formula, represents a polynomial with complex roots. That is: (
,
,
)
![D = b^{2}-4\cdot a\cdot c](https://tex.z-dn.net/?f=D%20%3D%20b%5E%7B2%7D-4%5Ccdot%20a%5Ccdot%20c)
![D = (-1)-4\cdot (1)\cdot (4)](https://tex.z-dn.net/?f=D%20%3D%20%28-1%29-4%5Ccdot%20%281%29%5Ccdot%20%284%29)
(Conjugated complex roots)
Step E
![(x-0.5-i\,1.936)\cdot (x-0.5+i\,1.936) = 0](https://tex.z-dn.net/?f=%28x-0.5-i%5C%2C1.936%29%5Ccdot%20%28x-0.5%2Bi%5C%2C1.936%29%20%3D%200)
Step F
![x = 0.5+i\,1.936\,\lor\,x = 0.5-i\,1.936](https://tex.z-dn.net/?f=x%20%3D%200.5%2Bi%5C%2C1.936%5C%2C%5Clor%5C%2Cx%20%3D%200.5-i%5C%2C1.936)
The answer is 5.5.
hope this helps!!
Answer: 2< x < 10, closed circle at 2 and 10, line inbetween them
Step-by-step explanation:
I think the anser is c that what i think
Answer:
<em>The probability of scoring two goals in both times is</em><em> 0.137 or 13.7%</em>
Step-by-step explanation:
Statistics show that a certain soccer player has a 63% chance of missing the goal each time he shoots.
So ![P(A)=0.63](https://tex.z-dn.net/?f=P%28A%29%3D0.63)
Hence, the probability of getting success in his shoots will be,
![P(A^c)=1-P(A)=1-0.63=0.37](https://tex.z-dn.net/?f=P%28A%5Ec%29%3D1-P%28A%29%3D1-0.63%3D0.37)
The probability of scoring two goals in both times is,
![=P(A^c)\cdot P(A^c)](https://tex.z-dn.net/?f=%3DP%28A%5Ec%29%5Ccdot%20P%28A%5Ec%29)
![=0.37\times 0.37](https://tex.z-dn.net/?f=%3D0.37%5Ctimes%200.37)
![=0.137](https://tex.z-dn.net/?f=%3D0.137)
![=13.7\%](https://tex.z-dn.net/?f=%3D13.7%5C%25)