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Crazy boy [7]
2 years ago
5

What is 3000 times 562

Mathematics
2 answers:
Karolina [17]2 years ago
7 0
1,686,000 is the correct answer
Ket [755]2 years ago
6 0

Answer:

1,686,000

Step-by-step explanation:

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AysviL [449]

Answer:

A. March

Step-by-step explanation:

You can tell by subtracting the tallest bar in the month from the shorter one, and seeing which number is bigger out of all of them.

Hope this helped :)

5 0
2 years ago
Read 2 more answers
On tuesday bill bought nine posters. On wednesday half of all the posters that he had were destroyed. On thursday there were onl
Anettt [7]
(x+9)/2+=24
        *2   I *2
      x+9=48
         -9    -9
x=39
4 0
3 years ago
How many 3/4 foot pieces can clark cut out from the 7 1/2 feet of wire
ivolga24 [154]
(7 1/2) / (3/4) = 
(15/2) / (3/4) =
15/2 * 4/3 =
30/3 =
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7 0
3 years ago
−4.2(−2.8+4.5)​ I think I know what the answer is but I just want to be 100% sure. Please solve this and tell me your answer. I
Talja [164]

Answer:

-7.14

Step-by-step explanation:

Evaluate

−4.2(−2.8 + 4.5)​

Open parenthesis

(-4.2 * -2.8) + (-4.2 * 4.5)

= (11.76) + (- 18.9)

= 11.76 - 18.9

= -7.14

NOTE:

Negative (-) × negative (-) = positive (+)

Positive (+) × positive (+) = positive (+)

Negative (-) × positive (+) = negative (-)

Positive (+) × negative (-) = negative (-)

7 0
3 years ago
Which of these relations on{0,1,2,3}are partial orderings? Determine the properties of a partial ordering that the others lack.
omeli [17]

Step-by-step explanation:

A = {0,1,2,3}

a): R = {(0,0),(2,2),(3,3)}

R is antisymmetric, because if the (a,b)∈R, than a=b.

R is not reflexive, because (1,1) ∉ R while 1 ∈ A.

R is transitive, because if the (a,b)∈R and (b, c) ∈ R, than a=b=c and (a,c)=(a,a)∈R.

R is not portable ordering because R is not reflexive.

b): R = {(0,0),(1,1),(2,0),(2,2),(2,3),(3,3)}

R is antisymmetric, because if the (a,b)∈R and if the (b, a) ∈ R, than a=b (since (2,0) ∈ R and (0,2) ∉ R; and (2,3) ∈ R and (3,2) ∉ R )

R is reflexive, because (a,a) ∈ R of every element a ∈ A.

R is transitive , because if the (a,b)∈R and if the ( b , c )∈R . then a = b or b = c ( since there are only two element not of the form ( a , a ) and that pair does not satisfy ( a,b ) ∈ R and ( b , a ) ∈ R ), which implies ( a , c ) = ( b , c ) ∈ R or ( a , c ) = ( a , b ) ∈ R.

R is a partial ordering, because R is reflexive, antisymmetric and transitive.

c): R =  {(0,0),(1,1),(1,2),(2,2),(3,1),(3,3)}

R is reflexive, because (a,a)∈R of every element a ∈ A.

R is antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R . then a = b ( since ( 1 , 2 )∈R and ( 2 , 1 ) ∉ R; ( 3 , 1 ) ∈ R and ( 1 , 3 ) ∉ R ).  

R is not transitive , because ( 3 , 1 ) ∈ R and ( 1 , 2 )∈R, while ( 3 , 2 ) ∈ R.

R is not a partial ordering. because R is not transitive .

d): R =  {(0,0),(1,1),(1,2),(1,3),(2,0),(2,2),(2,3), (3,0),(3,3)}

R is the reflexive, because ( a , a )∈R of every elements∈A.

R is the antisymmetric, because if the ( a , b )∈R and if the ( b , a )∈R, then a = b ( since ( 1 . 2 )∈R and ( 2 . 1 )∉R; similarly, all other elements not of the form (a,a) ).

R is not transitive, because ( 1 , 2 )∈R and ( 2 , 0 )∈R, while ( 1 . 0 )∉R.

R is not a partial ordering, because R is not transitive,

e):  R = { ( 0 , 0 ) , ( 0, 1 ) , ( 0 , 2 ) , ( 0 , 3 ) , ( 1 , 0 ) , ( 1 , 1 ) , ( 1 , 2 ) , ( 1 , 3 ) , ( 2 , 0 ) , ( 2 , 2 ) , ( 3 , 3 ) }

R is the reflexive , because ( a , a )∈R of every element a∈A .

R is not antisymmetric, because ( 1 , 0 )∈R and ( 0 , 1 )∈R while 0 is not equal to 1.

R is not transitive, because ( 2 , 0 )∈Rand ( 0 , 3 )∈R, while ( 2 , 3 )∉R .

R is not a partial ordering, because R is not the antisymmetric and not the transitive.

3 0
3 years ago
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