Given,
The sum of three integers is 92
So,
Let,
The first integer be "x"
The second integer be "y"
The third integer be "z"
Now,
According to the question,
y = 3x ..............equation (1)
z = 2x - 10 .............. equation (2)
x + y + z = 92 ..............equation (3)
Now,
Substituting the value of "y" and "z" from equation (1) and (2), we get,
x + (3x) + (2x - 10) = 92
x + 3x + 2x - 10 = 92
6x - 10 = 92
6x = 92 + 10
x = 102 / 6
x = 17
Now,
substituting the value of "x" in equation (1)
y = 3 (17)
y = 51
Now,
Substituting the value of "x" in equation (2),
z = 2 (17 ) - 10
z = 34 - 10
z = 24
So, the numbers are 17, 51 and 24
NEVER HATE MATH!!!
Answer:
B: (2, -1)
Step-by-step explanation:
1) First isolate the y in both equations
2) Set the equations equal to each other
3) Solve for x (you should get 2 and 5)
4) Insert the x values back in to get your y values
5) You should have gotten (2, -1) and (5, 2)
These are your two answers, but the question is only asking for one solution and (5,2) isn't one of the options, so it has to be (2,-1).
Answer:
Step-by-step explanation:
I'm guessing A and J. Makes the most sense.
So tripple of 3/4 is 3/4 times 3/1=9/4=2 and 1/4
she has 1 and 5/8
compare 1 and 5/8 and 2 and 1/4
convert 1/4 to 2/8
she has 1 and 5/8 but she needs 2 and 2/8
1=8/8
1 and 5/8 and needs 1 and 10/8
1 and 5/8+x=1 and 10/8
subtract 1
5/8+x=10/8
subtrarct 5/8
x=5/8
she must borrow 5/8 cups from neighbor
Mid point formula
(x1 + x2) , (y1+y2)
--------- --------
2 2
Thus for x it would be (6+(-2)) /2 or 4/2 or 2.
For y (-4 + 4) / 2 or 0 / 2 or 0.
Mid point is (2,0)
