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Shtirlitz [24]
3 years ago
14

PLEASE HELPPPPPPPP!!!!!

Mathematics
1 answer:
OlgaM077 [116]3 years ago
4 0

Answer:

3500

(0,3500)

Step-by-step explanation:

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Fourteen over twelve equals d over fourtyeight
damaskus [11]
56 because 12 divided by 48 is 4 and 14 times 4 equals 56.
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3 years ago
The square of a non-zero number is equal to 70% of the original number. What
aleksandr82 [10.1K]

Answer:

0.7.

Step-by-step explanation:

x^2 = 0.7x

x^2 - 0.7x = 0

x(x - 0.7) = 0

x = 0, 0.7.

3 0
2 years ago
Find the volume of the prism.
Minchanka [31]
Volume = L x W x H
In this case, it would be 24m x 4m x 2m = 192 meters cubed.
6 0
3 years ago
Find (f - g)(x) if f(x) = x2 ­- x - 6 and g(x) = 2x2 - 3x + 4
Nadya [2.5K]
For this question we just have to re-substitute the expressions for their respective functions by assigning them in a plausible condition for two functions. Here, the first function of "x" is subtracted by a second function of "x". The expressions are assigned according to the first and second function expressions in each case or condition.

All we have to do is distribute the parentheses for second expression to deploy positive addition between 2x^2 and 3x. Furthermore grouping all the like terms to get the required answer to this query. So, let me express this via LaTeX interpreter equation editor for a better understanding and clear all the doubts for these forms of queries.

\mathbf{Since, \: \: f(x) = x^2 - x - 6}

\mathbf{\therefore \quad \Big(x^2 - x - 6 - g(x) \Big) \: (x)}

\mathbf{Since, \: \: g(x) = 2x^2 - 3x + 4}

\mathbf{\therefore \quad x^2 - x - 6 - (2x^2 - 3x + 4)}

\mathbf{x^2 - x - 6 - (2x^2) - (- 3x) - (+ 4)}

\mathbf{x^2 - x - 6 - 2x^2 + 3x - 4}

\mathbf{x^2 - 2x^2 - x + 3x - 6 - 4}

\mathbf{x^2 - 2x^2 + 2x - 6 - 4}

\mathbf{- x^2 + 2x - 6 - 4}

\boxed{\mathbf{\underline{Required \: \: Answer: \: - x^2 + 2x - 10}}}

Hope it helps.
6 0
3 years ago
Show the steps<br> Find an equation of the line through (-1,4) and perpendicular to 2x+3y=8
kondaur [170]

Hello:

2x+3y=8

y =(-2/3)x+8/3  (the slope is : (-2/3) )

<span>an equation of the line through (-1,4) and perpendicular to 2x+3y=8</span>

<span> is : y = ax+b
the slope is a : a×(-2/3) = -1......( perpendicular to a line with a slope of -2/3)
a = 3/2          y=(3/2)x+b
the line that passes through (-1, 4) :4 = (3/2)(-1)+b
b =11/2
 the equation is :  y  = (3/2)x+11/2</span>

6 0
3 years ago
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