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Shalnov [3]
3 years ago
13

17.9 find the two square roots of the number

Mathematics
1 answer:
allochka39001 [22]3 years ago
6 0

Answer: 27.9 let me know if you need a another answer I hope this helps!

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Point A(1,9) and point B(−4,−3) are located within the coordinate plane.
AlekseyPX

Answer:

The answer to your question is 13 units

Step-by-step explanation:

Data

A (1, 9)

B (-4, -3)

distance = ?

Formula

distance = \sqrt{(x2 - x1)^{2} + (y2 - y1)^{2}}

Substitution

distance = \sqrt{(-4 - 1)^{2} + (-3 - 9)^{2}}

Simplification

distance = \sqrt{(-5)^{2} + (-12)^{2}}

distance = \sqrt{25 + 144}

distance = \sqrt{169}

Result

distance = 13

8 0
3 years ago
Read 2 more answers
Segment AB has endpoints at −2 and 12. What is the coordinate of its midpoint?
charle [14.2K]

Hi there!

\large\boxed{5}

Find the midpoint using the midpoint formula:

m = (p1 + p2) / 2

m = (-2 + 12) / 2

m = 10 / 2

m = 5.

3 0
3 years ago
Factor the expression 3x^(2)+10x+8
marin [14]

Hello,

If we want to factor the expression, we have to solve

3x² + 10x + 8 = 0

a = 3 ; b = 10 ; c = 8

∆ = b² - 4ac = 10² - 4 × 3 × 8 = 4 > 0

x1 = (-b - √∆)/2a = (-10 - 2)/6 = -12/6 = -2

x2 = (-b + √∆)/2a = (-10 + 2)/6 = -8/6 = -4/3

Factor :

a (x - x1)(x - x2)

= 3(x + 2)(x + 4/3)

= (x + 2)(3x + 4)

8 0
2 years ago
Hi, can someone please help me with this question!!! Thank you ☺
docker41 [41]
I think Hannah is right
6 0
3 years ago
Derive the equation of the parabola with a focus at (6, 2) and a directrix of y = 1
geniusboy [140]

Answer:

Step-by-step explanation:

eq. of directrix is y-1=0

let (x,y) be any point the parabola.

then\sqrt{ (x-6)^2+(y-2)^2}=\frac{y-1}{(-1)*2}

squaring

x²-12x+36+y²-4y+4=y²-2y+1

x²-12 x+40-1=4y-2y

2y=x²-12x+39=x²-12x+36+3

(x-6)²=2y-3

5 0
3 years ago
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