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4 years ago

What is the value 6=a/4+2

Mathematics

1 answer:

Tpy6a [65]4 years ago

7 0

Answer:

a=16

Step-by-step explanation:

16/4+2 = 6

Thus the answer is 16

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OLga [1]

Answer:2

Step-by-step explanation:

It can't be 1 because -4 < or equal to 2-6 is still less than or equal to 8 and it has to be 2 since -4 < or equal to 2-12 is not a correct statement even though it is less than or equal to 8 and it isn't -1 or 0 either

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4 years ago

For what value of x does g(x) =0 ?

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Step-by-step explanation:

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3 years ago

Arron spends 1/2 of his $800 weekly wage on rent and 1/4 on repaying the loan for his car. How much money does he have left for

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Step-by-step explanation:

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4 years ago

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Step-by-step explanation:

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2 years ago

Given 1+cosx\sinx+sinx\1+cosx=4, find a numerical value of one trigonometric function of x.

Len [333]

Answer:

Option d. $sin(x)=\frac{1}{2}$

Step-by-step explanation:

<u><em>The complete question is</em></u>

Given (1+cosx)/(sinx) + (sinx)/(1+cosx) =4, find a numerical value of one trigonometric function of x.

a. tanx=2

b. sinx=2

c. tanx=1/2

d. sinx=1/2

we have

$\frac{1+cos(x)}{sin(x)}+\frac{sin(x)}{1+cos(x)}=4$

Find the common denominator and adds the fractions

$\frac{(1+cos(x))^2+sin^2(x)}{(1+cos(x))sin(x)}=4$

Expanded the numerator

$\frac{(1+2cos(x)+cos^2(x)+sin^2(x)}{(1+cos(x))sin(x)}=4$

Remember that

$sin^2(x)+cos^2(x)=1$ ----> trigonometric identity

substitute

$\frac{1+2cos(x)+1}{(1+cos(x))sin(x)}=4$

$\frac{2+2cos(x)}{(1+cos(x))sin(x)}=4$

Factor 2 in the numerator

$\frac{2(1+cos(x))}{(1+cos(x))sin(x)}=4$

Simplify

$\frac{2}{sin(x)}=4$

$sin(x)=\frac{1}{2}$

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3 years ago