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3 years ago

If x = -2/3 and y = 27, what is the value of xy + 5/3 ?

Mathematics

2 answers:

Svetlanka [38]3 years ago

7 0

Answer:

Step-by-step explanation:

Evaluate the numerator , that is

xy + 5 = ( - $\frac{2}{3}$ × 27 ) + 5 = - 18 + 5 = - 13 , then

$\frac{-13}{3}$

= - $\frac{13}{3}$ → B

Fittoniya [83]3 years ago

6 0

Answer:

b) $\frac{-13}{3}$

Step-by-step explanation:

$\frac{xy + 5}{3}\\\\\frac{\frac{-2}{3}27 + 5}{3}\\\\\frac{-18 + 5}{3}\\\\\frac{-18 + 5}{3}\\\\\frac{-13}{3}$

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3 years ago

If it is 85°C in California and -4°C is Nebraska, how many degrees warmer is it in California? Explain how

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Answer:

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2 years ago

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If x3 - kx2 - 13x + 10 is divided by (x + 2), the remain is 4. Find the value of k using the remainder theorem.

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3 years ago

Find the mean, μ, for the binomial distribution with n = 48 and p = 3/5. Round your answer to the nearest hundredth. A) μ = 29.7

qaws [65]

The mean of the binomial distribution is (d) μ = 28,8

<h3>How to determine the mean?</h3>

The given parameters of the binomial distribution are given as:

n = 48 and p = 3/5

The mean is then calculated using:

μ = np

This gives

μ = 48 * 3/5

Evaluate

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Read more about mean at:

brainly.com/question/15858152

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2 years ago

A positive real number is 2 less than another. When 4 times the larger is added to the square of the smaller, the result is 49.

Kobotan [32]

Answer:

The numbers are

$-2+3\sqrt{5}$ and $3\sqrt{5}$

Step-by-step explanation:

Let

x -----> the smaller positive real number

y -----> the larger positive real number

we know that

A positive real number is 2 less than another

$x=y-2$

$y=x+2$ ----> equation A

When 4 times the larger is added to the square of the smaller, the result is 49

$4y+x^2=49$ ----> equation B

substitute equation A in equation B

$4(x+2)+x^2=49$

solve for x

$x^2+4x-41=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+4x-41=0$

$a=1\\b=4\\c=-41$

substitute in the formula

$x=\frac{-4\pm\sqrt{4^{2}-4(1)(-41)}} {2(1)}$

$x=\frac{-4\pm\sqrt{180}} {2}$

$x=\frac{-4\pm6\sqrt{5}} {2}$

$x=-2\pm3\sqrt{5}$

The positive real number is

$x=-2+3\sqrt{5}$

Find the value of y

$y=x+2$

$y=-2+3\sqrt{5}+2$

$y=3\sqrt{5}$

6 0

4 years ago