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Valentin [98]
3 years ago
13

Can someone help me with this?

Mathematics
1 answer:
AfilCa [17]3 years ago
3 0
The box does not let me write in it....

You might be interested in
Question 13. Please
Sonbull [250]

Answer:

d

Step-by-step explanation:

Δ OPG is right with hypotenuse OG being the radius of the circle

Using Pythagoras' identity in the right triangle

OG² = OP² + PG²

[ PG = 11 , since OP is the perpendicular bisector of FG ]

OG² = 8² + 11² = 64 + 121 = 185

Δ OQS is right with hypotenuse OS being the radius

Using Pythagoras' identity

OS² = QS² + OQ² , that is

185 = 13² + x²

185 = 169 + x² ( subtract 169 from both sides )

16 = x² ( take the square root of both sides )

4 = x → d

8 0
2 years ago
Im to lazy please help.. ;-;
Mumz [18]

Step-by-step explanation:

18h=252

9h=?(x)

9×252=18x

2268=18x

2268/18=x

x=126

5 0
3 years ago
A group of eight golfers paid $430 to play a round of golf . Of the golfers one was a member and 7 were not what is the cost for
charle [14.2K]

Answer:

Incomplete question

Complete question;

A group of eight golfers paid $430 to play a round of golf . Of the golfers one was a member and 7 were not.

Another group of golfers consists of two members and one nonmember. They paid a total of $75. What is the cost for a member to play a round of golf, and what is the cost for a nonmember?

Answer: X = $82.695 for members

Y = $49.615 for non members

Step-by-step explanation:

Let's use X to denote members and Y for non-members.

Therefore, amount paid by one member to play + amount paid by 7 non-members to play = 430

X + 7Y = 430. . .1

Amount paid by 2 members to play + amount paid by one non-member to play = 215

2X + Y = 215. . .2

Solving both equations simultaneously

X+7Y = 430

2X +Y = 215

Therefore, from eqn 1. X = 430-7y

Substituting this into wan 2 gives

2(430-7Y) + Y = 215

860-14Y + Y = 215

860-215 =13Y

645 = 13y

Y = 49.615

Therefore substituting Y = 49.615 into any equation above

X + 7(49.615) = 430

X = 430-347.05

X = 82.695

3 0
3 years ago
A booklet is made from 6 rectangular pieces of paper. Each piece measures 297mm by 420mm. The mass of paper is 80g per m^2. What
liq [111]
Alright, so the area of one paper is 297mm*420mm=124740mm^2. Multiplying that by 6 due to 6 sheets, we get 748440mm^2. Converting mm^2 to m^2, since we know that 1000mm=1m, we simply do (1m/1000m)^2=1m^2/1,000,000mm^2. Our equation is now
748440mm^2*1m^2/1,000,000mm^2=0.748440m^2 by crossing out the millimeters. Lastly, since it's 80g/1m^2, we multiply our number by that to get 59.8752g
3 0
3 years ago
A rectangular lawn is 24 feet wide by 32 feet long. A sidewalk will be built along the inside edges of all four sides. The remai
levacccp [35]
So the original lawn has an area
24 × 32 = 768 the new lawn will have area 425
this means the area of the sidewalk will be 768-425=343
now the sidewalk is a certain width of we draw it out and label it x we see the lawn has an area of
(32 - 2x)(24 - 2x) = 425 \\ 768 - 64x - 48x + 4 {x}^{2}  = 425 \\ 4 {x}^{2}  - 112x  + 343 = 0
use the quadratic formula to solve. then you will know how wide the sidewalk is. I will attach picture

5 0
3 years ago
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