3 years ago

Rewrite (−4)^2/7 in radical form.

1 answer:

7 0

Answer:

^7√(-4)^2 or 1.48 I hope it helps

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TiliK225 [7]

$\sqrt[5]{x^5}=x\\\\32^\frac{3}{5}=\left(32^\frac{1}{5}\right)^3=\left(\sqrt[5]{32}\right)^3=2^3=8$

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3 years ago

melomori [17]

The value of x would be 5 for the model 2x+4.

Rearrange unknown terms to the left side of the equation,
$= > 2x-3x = -1 - 4$

Combine like terms $= -x = -1-4$

By calculating the sum or difference : -x = -5

Lets divide both sides of the equation by the resulting coefficient 5
So x = 5

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Learn more about algebra equations refer:

https://brainly.in/question/7037012

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2 years ago

Yuri [45]

Answer:

F'(x)=4x3+16x

Step-by-step explanation:

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2 years ago

frez [133]

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2 years ago

Aleksandr-060686 [28]

Answer:

Option : D

Step-by-step explanation:

Hope it helps you!

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3 years ago