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Nataly [62]
3 years ago
10

How many sixteenths are in 15/16

Mathematics
2 answers:
elena55 [62]3 years ago
7 0
To get this, you need to divide 15/16 by 1/16. To do it, multiply 15/16 by 16 and you get 15 as your answer.
scZoUnD [109]3 years ago
4 0

Answer:15

Step-by-step explanation:

Since a sixteenth is represented by 1/16

Hence to find out the number of sixteenth in

15/16 we have to divide it by 1/16

We have (15/16)/1/16

Simplifying we have 15/16*16/1

Hence we have 15.

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Which of the expressions below has a 6 in the hundredths place of the product? Select all that apply.
Sliva [168]

Answer:

A

Step-by-step explanation:

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3 years ago
At the end of summer all sandals are marked down by 70%. If a pair of sandals originally cost $19.50, how much will it cost at t
aleksley [76]
70 percent off 19.50 would mean getting a discount of 13.65, so the final price of the sandals by the end of the summer should be 5.85
5 0
3 years ago
Sharise Brody folds and glues corrugated cardboard boxes at the rate of $0.57 per box. If she averages 40 boxes per hourhow much
Valentin [98]

Answer:

she makes $22.80 a day

Step-by-step explanation:

since she makes $0.57 per box and averages at 40 boxes a day, we multiply 40 and 0.57. 40 x 0.57 = 22.8, or $22.80.

hope this helped!

6 0
2 years ago
What is the missing number?
JulsSmile [24]

Answer:

y = 2^{x}

Step-by-step explanation:

Given the above data for x and y.

From the algebraic expression;

y = 2^{x}

We can deduce that the value of y is equal to two (2) raise to the power of x.

When x = 1, y = 2

y = 2^{x}

y = 2^{1}

y = 2

When x = 2, y = 4

y = 2^{x}

y = 2^{2}

y = 4

When x = 3, y = 8

y = 2^{x}

y = 2^{3}

y = 8

The above calculations can be used to determine the other values of y with respect to x.

3 0
3 years ago
A box with a square base and an open top is being constructed out of A cm2 of material. If the volume of the box is to be maximi
viktelen [127]

Answer:

Side length = \sqrt{\frac{A}{3} } cm ,   Height =  \frac{1}{2} \sqrt{\frac{A}{3} } cm  ,  Volume = \frac{A\sqrt{A}}{6\sqrt{3} }  cm³

Step-by-step explanation:

Assume

Side length of base = x

Height of box = y

total material required to construct box = A ( given in question)

So it can be written as

A = x² + 4xy

4xy = A - x²

  1. y = \frac{A - x^{2} }{4x}

Volume of box = Area x height

V = x² ₓ y

V = x² ₓ ( \frac{A - x^{2} }{4x} )

V =  \frac{Ax - x^{3} }{4}

To find max volume put V' = 0

So taking derivative equation becomes

\frac{A - 3 x^{2} }{4} = 0

A = 3 x^{2}

x^{2} = \frac{A}{3}

x = \sqrt{\frac{A}{3\\} }

put value of x in equation 1

y = \frac{A - \frac{A}{3} }{4\sqrt{\frac{A}{3} } }  

y = \frac{2 \sqrt{\frac{A}{3} } }{4 \sqrt{\frac{A}{3} } }

y = \frac{1}{2} \sqrt{\frac{A}{3} }

So the volume will be

V = x^{2} × y

Put values of x and y from equation 2 & 3

V = \frac{A}{3} (\frac{1}{2} \sqrt{\frac{A}{3} } )

V = \frac{A\sqrt{A}}{6\sqrt{3} }

8 0
4 years ago
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