<span>c)1 + 2cot^2x + 2cscx cotx
because cosc^2x=1+cot^2x</span>
Answer:
the maximum number of crates that can be stacked between the floor and ceiling
where 1 foot = 12 inches. SO the answer is that a maximum of 10 crates can be stacked from floor to ceiling.
Step-by-step explanation:
i) the maximum number of crates that can be stacked between the floor and ceiling
where 1 foot = 12 inches
I know this is kinda late, but...
You can solve this easily as long as you remember how to find the volume of a cube. v=a^3, when a means length. The length is 1/2 cm, or .5 cm.
So, v+.5^3, which equals .125 cm. Each cube has a that volume. Now, multiply that by how many actual cubes there are, 96.
96 * .125 = 12
The answer would be 2,700,000.
This is because of the rules of rounding.
If a digit is 4 or smaller, it rounds down.
If a digit is 5 or more, it rounds up.
The number is 2, 746, 052 so it stays at 700,000.
TLDR: 2,700,000
