What is the fraction and decimal

What is the slope of the way y-3=-4(x-5)

mash [69]

The answer to the question is y=-4x+23

5 0

4 years ago

The volume of a rectangular prism is (x4 + 4x3 + 3x2 + 8x + 4), and the area of its base is (x3 + 3x2 + 8). If the volume of a r

muminat

x + 1 minus StartFraction 4 Over x cubed + 3 x squared + 8

Step-by-step explanation:

Volume of the prism is given by the product of its base area and height. To get the height, divide the volume by the base area

Perform long division of the volume polynomial by the polynomial for base area to get the polynomial for height

x³+3x²+8 √x⁴+4x³+3x²+8x+4

-x⁴+3x³+8x

---------------------------

1x³+3x²+0+4

- 1x³+3x²+8

------------------------

-4

The answer will be : x+1 + -4/(x³+3x²+8)

Learn More

Dividing polynomials : brainly.com/question/11792208

Keywords : volume, rectangular prism, area,height

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3 0

3 years ago

Read 2 more answers

What happens to the width of a confidence interval for a population mean if the level of confidence is increased without changin

natulia [17]

Answer: If the level of confidence is increased without changing the sample size then The margin of error will decrease because the critical value will decrease. The decreased margin of error will cause the confidence interval to be narrower.

where;

Margin of error = Critical value × Standard deviation

Here, it can be duly noted that Margin of error has a positive relation with critical value, i.e The margin of error will decrease because the critical value will decrease.

whereas;

The confidence interval is the value ± the margin of error.

Therefore, the decreased margin of error will cause the confidence interval to be narrower.

7 0

4 years ago

Coco's garden has 888 tomato plants, 444 pepper plants, 333 squash plants, and 666 pumpkin plants.

AveGali [126]

888 + 444 + 333 + 666 = 2331 / 7 = 3

3 * 222 = 666

There are 666 of the plants

I hope this helps :)

6 0

3 years ago

Read 2 more answers

The arch beneath a bridge is semi-elliptical, a one-way roadway passes under the arch. The width of the roadway is 38 feet and

forsale [732]

Answer:

Only truck 1 can pass under the bridge.

Step-by-step explanation:

So, first of all, we must do a drawing of what the situation looks like (see attached picture).

Next, we can take the general equation of an ellipse that is centered at the origin, which is the following:

$\frac{x^2}{a^2}+\frac{y^2}{b^2}$

where:

a= wider side of the ellipse

b= shorter side of the ellipse

in this case:

$a=\frac{38}{2}=19ft$

and

b=12ft

so we can go ahead and plug this data into the ellipse formula:

$\frac{x^2}{(19)^2}+\frac{y^2}{(12)^2}$

and we can simplify the equation, so we get:

$\frac{x^2}{361}+\frac{y^2}{144}$

So, we need to know if either truk will pass under the bridge, so we will match the center of the bridge with the center of each truck and see if the height of the bridge is enough for either to pass.

in order to do this let's solve the equation for y:

$\frac{y^{2}}{144}=1-\frac{x^{2}}{361}$

$y^{2}=144(1-\frac{x^{2}}{361})$

we can add everything inside parenthesis so we get:

$y^{2}=144(\frac{361-x^{2}}{361})$

and take the square root on both sides, so we get:

$y=\sqrt{144(\frac{361-x^{2}}{361})}$

and we can simplify this so we get:

$y=\frac{12}{19}\sqrt{361-x^{2}}$

and now we can evaluate this equation for x=4 (half the width of the trucks) so:

$y=\frac{12}{19}\sqrt{361-(8)^{2}}$

y=11.73ft

this means that for the trucks to pass under the bridge they must have a maximum height of 11.73ft, therefore only truck 1 is able to pass under the bridge since truck 2 is too high.

5 0

3 years ago