K= 10(-7) -19
k= -70-19
k=-89
Alright, so it would be helpful to think about this question in terms of units. You're given a distance (meters) and speed (meters per second). You're asked for time (which is in seconds).
If you do

, your answer will be in seconds. So divide your distance (2.28 x 10^11 meters) by your speed (3.00 x 10^8 meters/second), and you should get your time!
Their sum can be both equal, or greater. If you have 3/8 and 6/8, you would get 9/8 or 1 and 1/8. Which is greater than 1. Also if you add 2/6 and 4/6, you get 6/6 or 1. proving that both are possible.
M is your answer, because the tangent intersects the circle at point M.
So M is correct.
Answer:
Option D. y = 5x + 1
Step-by-step explanation:
From the question given above, the following data were:
Input (x) >>>>>> Output (y)
0 >>>>>>>>>>>> 1
1 >>>>>>>>>>>> 6
2 >>>>>>>>>>>> 11
3 >>>>>>>>>>>> 16
4 >>>>>>>>>>>> 21
To know the the correct answer to the question, we shall apply the equation given in each option to see which will satisfy the table. This can be obtained as follow:
For Option a
y = 3x + 3
x = 0
y = 3(0) + 3
y = 0 + 3
y = 0
y = 3x + 3
x = 1
y = 3(1) + 3
y = 3 + 3
y = 6
For Option b
y = 5x – 4
x = 0
y = 5(0) – 4
y = 0 – 4
y = – 4
y = 5x – 4
x = 1
y = 5(1) – 4
y = 5 – 4
y = 1
For Option c
y = 10x – 9
x = 0
y = 10(0) – 9
y = 0 – 9
y = – 9
y = 10x – 9
x = 1
y = 10(1) – 9
y = 10 – 9
y = 1
For Option d
y = 5x + 1
x = 0
y = 5(0) + 1
y = 0 + 1
y = 1
y = 5x + 1
x = 1
y = 5(1) + 1
y = 5 + 1
y = 6
From the illustrations made above, only option d satisfy the table. Thus, option d gives the correct answer to the question.