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3 years ago

Find each measurement indicated. Round your answers to the nearest tenth.

Mathematics

1 answer:

Law Incorporation [45]3 years ago

5 0

Answer:

52.08°

Step-by-step explanation:

Law of sine: $\frac{93}{25}$ = $\frac{x}{14}$

93*14=25x

1302=25x

52.08=x

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How do I work this problem out.

astraxan [27]

First you should find the area of the rectangle in the middle.
A: 9 x 6 = 54
Then you can find the area of the triangle on the right.
A: 6 x 5 = 30/2 = 15
Then you can do the triangle on the right.
11-9 = 2
A: 2 x 6 = 12/2 = 6
Then you can add it all together.
15 + 6 + 54 = 74
So the area of the irregular shape is 74.

I hope this helps!

7 0

3 years ago

Read 2 more answers

State the property that justifies each statement:1. If 80 mA, then me = 802. If RS - TU and TU = YP, then RS = YP2.3. If 7x 28,

BabaBlast [244]

Question 3

if 7x = 28

divide both sides by 7

7x/7 = 28/7

x = 4

This is division property of equality

Question 1

if angle m is 80 degrees the m = 80 degrees

this can be a congruent angles or alternate angles are equal

this is symmetric property of equality

Question 5

m1 = 30 and mz1 = m2, then m2 = 30

this property is transitive property of equality

Question 2

if RS - TU and TU =YP, then RS = YP

this means you can substitute RS with YP

then we have our new expression as

YP - YP

this is substitution property of equality, this is because we are substituting a function with another function

4 0

1 year ago

Which number is closest to - 102 (square root)? A. -11.5 B. -10.0 C. -9.7 D. -11.1

andre [41]

Answer:

B. -10.0

Step-by-step explanation:

-10.0² = -100

thus= -10.0 is the closest to -102 (square root)

3 0

3 years ago

Read 2 more answers

What is the ratio of 3ft to 5in

shtirl [24]

Im not that sure but i think it is 5

8 0

3 years ago

The mean MCAT score 29.5. Suppose that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.

Paul [167]

Answer:

We conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

Step-by-step explanation:

We are given that the Kaplan tutoring company obtains a sample of 40 students with a mean MCAT score of 32.2 with a standard deviation of 4.2.

Let $\mu$ = population mean score

So, Null Hypothesis, $H_0$ : $\mu \leq$ 29.5 {means that the students that took the Kaplan tutoring have a mean score less than or equal to 29.5}

Alternate Hypothesis, $H_A$ : $\mu$ > 29.5 {means that the students that took the Kaplan tutoring have a mean score greater than 29.5}

The test statistics that will be used here is One-sample t-test statistics because we don't know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{s}{\sqrt{n} } }$ ~ $t_n_-_1$

where, $\bar X$ = sample mean MCAT score = 32.2

s = sample standard deviation = 4.2

n = sample of students = 40

So, the test statistics = $\frac{32.2-29.5}{\frac{4.2}{\sqrt{40} } }$ ~ $t_3_9$

= 4.066

The value of t-test statistics is 4.066.

Now, at 0.05 level of significance, the t table gives a critical value of 1.685 at 39 degrees of freedom for the right-tailed test.

Since the value of our test statistics is more than the critical value of t as 4.066 > 1.685, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region.

Therefore, we conclude that the students that took the Kaplan tutoring have a mean score greater than 29.5.

3 0

3 years ago