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Klio2033 [76]
3 years ago
14

X^2 +1/x^2+12(x+1/x) +38, ​

Mathematics
1 answer:
sergiy2304 [10]3 years ago
5 0

Answer:

44

Step-by-step explanation:

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Pls help , giving brainliest
11111nata11111 [884]

Answer:

(-5),-2)=-7

(-5,-6)=-11

is 77 all

8 0
3 years ago
Read 2 more answers
Want to check if I got the correct answer, thank you
SOVA2 [1]

To find:

The division of the polynomial.

Solution:

The division in given in the image below:

Thus, the result is:

x^3+3x^2-1x-5-\frac{11}{x+3}

Option D is correct.

3 0
1 year ago
Mary earns $6 per hour as a waitress. Last week she took home her regular earnings of $6 per hour plus $185 in tips for a total
Daniel [21]
Mary worked 22 hours.


To solve first you would subtract the amount she made in tips from her total earnings (317-185)
= 132
Then you divide that answer by her hourly salary of $6 (132/6)
=22
7 0
3 years ago
Which expression shows a way to find 50% of 632
Ilya [14]

Answer:

Well 50% of 632 is 316 but i need to see the expressions to be sure

Step-by-step explanation:

3 0
3 years ago
You have a wire that is 20 cm long. You wish to cut it into two pieces. One piece will be bent into the shape of a square. The o
Aleksandr [31]

Answer:

Therefore the circumference of the circle is =\frac{20\pi}{4+\pi}

Step-by-step explanation:

Let the side of the square be s

and the radius of the circle be r

The perimeter of the square is = 4s

The circumference of the circle is =2πr

Given that the length of the wire is 20 cm.

According to the problem,

4s + 2πr =20

⇒2s+πr =10

\Rightarrow s=\frac{10-\pi r}{2}

The area of the circle is = πr²

The area of the square is = s²

A represent the total area of the square and circle.

A=πr²+s²

Putting the value of s

A=\pi r^2+ (\frac{10-\pi r}{2})^2

\Rightarrow A= \pi r^2+(\frac{10}{2})^2-2.\frac{10}{2}.\frac{\pi r}{2}+ (\frac{\pi r}{2})^2

\Rightarrow A=\pi r^2 +25-5 \pi r +\frac{\pi^2r^2}{4}

\Rightarrow A=\pi r^2\frac{4+\pi}{4} -5\pi r +25

For maximum or minimum \frac{dA}{dr}=0

Differentiating with respect to r

\frac{dA}{dr}= \frac{2\pi r(4+\pi)}{4} -5\pi

Again differentiating with respect to r

\frac{d^2A}{dr^2}=\frac{2\pi (4+\pi)}{4}    > 0

For maximum or minimum

\frac{dA}{dr}=0

\Rightarrow \frac{2\pi r(4+\pi)}{4} -5\pi=0

\Rightarrow r = \frac{10\pi }{\pi(4+\pi)}

\Rightarrow r=\frac{10}{4+\pi}

\frac{d^2A}{dr^2}|_{ r=\frac{10}{4+\pi}}=\frac{2\pi (4+\pi)}{4}>0

Therefore at r=\frac{10}{4+\pi}  , A is minimum.

Therefore the circumference of the circle is

=2 \pi \frac{10}{4+\pi}

=\frac{20\pi}{4+\pi}

4 0
3 years ago
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