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vovikov84 [41]
3 years ago
15

Find the value of given expression

qrt{8100} " alt=" \sqrt{8100} " align="absmiddle" class="latex-formula">
​
Mathematics
2 answers:
Andrew [12]3 years ago
8 0
90 is the answer for the question
Doss [256]3 years ago
6 0

Answer:

90 is the answers for the question

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Shannon test-drives a car in Germany and drives 95 kilometers per hour. What is her speed in the miles per hour ?
Reptile [31]

Answer:

59.0303 miles per hour

Step-by-step explanation:

8 0
3 years ago
What part of 1.25 cm is 0.5 cm?
Kisachek [45]

Answer:

I dont know if you mean .05, but if you do mean that it would be the hundredths place. (if this isnt the right one I'm sorry.)

5 0
3 years ago
Read 2 more answers
In Triangle ABC, the length of Segment AB is equal to the length of segment AC. The length of segment BC is 4 less than twice th
seraphim [82]

Step-by-step explanation:

Let x be the length of segment AB.

Then the length of segment BC is (2x - 4).

The length of segment AC is x.

We know that x + (2x - 4) + x = 52.

Therefore 4x - 4 = 52, 4x = 56, x = 14.

Hence the length of segment AB is 14.

7 0
3 years ago
High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers
Maurinko [17]

Answer:

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(536.46, 603.54)

Step-by-step explanation:

<u><em>Step:-1</em></u>

Given that the mean of the Population = 540HP

Given that the size of the sample  'n' = 9

Given that the mean of the sample = 570HP

Given that the sample standard deviation = 30HP

<u><em>Step(ii):-</em></u>

<u><em>Degrees of freedom = n-1 =9-1 =8</em></u>

<u><em>t₀.₀₀₅ = 3.3554</em></u>

The 99% of a confidence interval for the average maximum HP for the experimental engine.

(x^{-} - t_{\frac{0.01}{2} ,8} \frac{S.D}{\sqrt{n} } ,x^{2}  + t_{\frac{0.01}{2},8 } \frac{S.D}{\sqrt{n} } )

(570-3.354\frac{30}{\sqrt{9} } , 570+3.354\frac{30}{\sqrt{9} } )

(570 - 33.54 , 570+33.54)

(536.46 , 603.54)

<u><em>Final answer</em></u> :-

<em>The 99% of a confidence interval for the average maximum HP for the experimental engine.</em>

<em>(536.46, 603.54)</em>

<em></em>

4 0
3 years ago
Suppose PR = 54, solve for QR<br> 4x-1<br> 3x-1<br> P<br> R
Svet_ta [14]

Answer:

QR = 23

Step-by-step explanation:

P, A, and R are collinear.

PR = 54

PQ = 4x - 1

QR = 3x - 1

To solve for the numerical length of PR, let's generate an equation to find the value of x.

According to the segment addition postulate:

PQ + QR = PR

(4x - 1) + (3x - 1) = 54 (substitution)

Solve for x

4x - 1 + 3x - 1 = 54

Combine like terms

4x + 3x - 1 - 1 = 54

7x - 2 = 54

Add 2 to both sides

7x - 2 + 2 = 54 + 2

7x = 56

Divide both sides by 7

\frac{7x}{7} = \frac{56}{7}

x = 8

QR = 3x - 1

Plug in the value of x into the equation

QR = 3(8) - 1 = 24 - 1

QR = 23

5 0
3 years ago
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