Question

(8v3-80v2+6)\(v-10)

Answer 1

$\frac{(8v^3-80v^2+6)}{v-10}$

Use long division for dividing

$(8v^3-80v^2+6)$ Here 'v' term is missing so we use 0vW

Divide $(8v^3-80v^2+0v+6)$ by v-10 using long division

Step 1: Put 8v^2 at the top

step 2: multiply 8v^2 with v-10  and put it at the bottom

step 3: subtract it

We will get remainder 6

so quotient is  $8v^2$

Remainder is 6