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dlinn [17]
2 years ago
11

5. CD has an endpoint at (2, -1) and a midpoint at (8,3). Which measure is closest to the length of CD?

Mathematics
1 answer:
Alexus [3.1K]2 years ago
8 0

Answer: C

Step-by-step explanation:

the equation for X is

\frac{2+x}{2} =\frac{8}{1}  use proportion to solve

2 + x = 16

x = 14

(14,y)

The equation for Y is

\frac{-1+y}{2} =\frac{3}{1} use proportion to solve

-1 + y = 6

y = 7

(14,7)

now use the distance formula

(14,7) (2,-1)

which gets you 14.4 or C

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Hanson and his classmates placed colored blocks on a scale during a science lab. The blue block weighed 8.1 pounds and the green
Alexeev081 [22]

Answer:

4.342

Step-by-step explanation:

8.1 - 3.758 = 4.342

When you are trying to find the amount of difference between two values you subtract the value less than the other and there you go, the solution!

I hope it was as simple as that and that this helped!

3 0
2 years ago
How do I solve this?
KengaRu [80]

Answer with Step-by-step explanation:

The given differential euation is

\frac{dy}{dx}=(y-5)(y+5)\\\\\frac{dy}{(y-5)(y+5)}=dx\\\\(\frac{A}{y-5}+\frac{B}{y+5})dy=dx\\\\\frac{1}{100}\cdot (\frac{10}{y-5}-\frac{10}{y+5})dy=dx\\\\\frac{1}{100}\cdot \int (\frac{10}{y-5}-\frac{10}{y+5})dy=\int dx\\\\10[ln(y-5)-ln(y+5)]=100x+10c\\\\ln(\frac{y-5}{y+5})=10x+c\\\\\frac{y-5}{y+5}=ke^{10x}

where

'k' is constant of integration whose value is obtained by the given condition that y(2)=0\\

\frac{0-5}{0+5}=ke^{20}\\\\k=\frac{-1}{e^{20}}\\\\\therefore k=-e^{-20}

Thus the solution of the differential becomes

 \frac{y-5}{y+5}=e^{10x-20}

5 0
3 years ago
Read 2 more answers
On 8(x - 2) + 3 = -61?
DochEvi [55]

Answer:

Hey there!

8(x-2)+3=-61

8(x-2)=-64

x-2=-8

x=-6

Let  me know if this helps :)

3 0
2 years ago
Read 2 more answers
the rectangular metallic block is 30cm long ,25cm broad and8cm high.how many pieces of rectangular slices each of 5mm thick can
Dmitrij [34]

Answer:

12

Step-by-step explanation:

cuz if u put all the fives it takes up for it u would get 12 times five

8 0
2 years ago
Julio's father is 4 times as old as Julio. The sum of their ages is no less than 55.
seropon [69]
Call (F) the age of the father and (J) the age of Julio

The F & J are related in this way: F=4J

 Now you have a restriction in the form of inequality: The sum of both ages has to be greater or equal than 55.

Algebraically that is: F + J ≥ 55

You can substitute F with 4J to find the solution for J: 

4J + J ≥ 55

5J ≥ 55

Now divide both sides by 5

5J/5 ≥ 55/5

J ≥ 11 

That Imposes a lower boundary for the value of J of 11, meaning that the youngest age of Julio can be 11
8 0
3 years ago
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