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Alenkinab [10]
3 years ago
8

If x=3, Solve, -3x +4 *

Mathematics
2 answers:
cricket20 [7]3 years ago
4 0

Answer:

-5

Step-by-step explanation:

-3 times 3 = -9 then add 4 and u get -5

eduard3 years ago
3 0

Answer:

-5

Step-by-step explanation:

3x -3 = -9 + 4 = -5

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5. Jared is playing a game that involves rolling a die and flipping a coin. 6. Please describe an event that may occur in this g
Andre45 [30]

An event that may occur in the game is you roll a  and get a tail.

The probability that he will roll a 5 and get a head is 1 / 12.

<h3>What is the probability?</h3>

Probability determines the chances that an event would happen. The probability the event occurs is 1 and the probability that the event does not occur is 0.

The probability that he will roll a 5 and get a head = (Number of sides with a 5 / number of sides in a cube) x (number of sides with a head / number of sides in a coin)

1/6 x 1/2 =  1 / 12.

To learn more about probability, please check: brainly.com/question/13234031

#SPJ1

3 0
2 years ago
Preform the indicated operation 5/8+7/12?
Vlad [161]

Answer:

5/8 + 7/12 =29/24

Step-by-step explanation:

8 0
3 years ago
B) Simplify 9y - 6y + y
julsineya [31]

Answer:

The answer is 4y

Step-by-step explanation:

Simplify the expression.

Hoped this helped!

Could I perhaps get brainly?

8 0
2 years ago
Read 2 more answers
Find the dimensions of the open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by
a_sh-v [17]

Answer:

Dimension of the box is 16.1\times 7.1\times 2.45

The volume of the box is 280.05 in³.

Step-by-step explanation:          

Given : The open rectangular box of maximum volume that can be made from a sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

To find : The dimensions and the volume of the box?

Solution :

Let h be the height of the box which is the side length of a corner square.

According to question,

A sheet of cardboard 21 in. by 12 in. by cutting congruent squares from the corners and folding up the sides.

The length of the box is L=21-2h

The width of the box is W=12-2h

The volume of the box is V=L\times W\times H

V=(21-2h)\times (12-2h)\times h

V=(21-2h)\times (12h-2h^2)

V=252h-42h^2-24h^2+4h^3

V=4h^3-66h^2+252h

To maximize the volume we find derivative of volume and put it to zero.

V'=12h^2-132h+252

0=12h^2-132h+252

Solving by quadratic formula,

h=\frac{-b\pm\sqrt{b^2-4ac}}{2a}

h=\frac{-(-132)\pm\sqrt{132^2-4(12)(252)}}{2(12)}

h=\frac{132\pm72.99}{24}

h=2.45,8.54

Now, substitute the value of h in the volume,

V=4h^3-66h^2+252h

When, h=2.45

V=4(2.45)^3-66(2.45)^2+252(2.45)

V\approx 280.05

When, h=8.54

V=4(8.54)^3-66(8.54)^2+252(8.54)

V\approx -170.06

Rejecting the negative volume as it is not possible.

Therefore, The volume of the box is 280.05 in³.

The dimension of the box is

The height of the box is h=2.45

The length of the box is L=21-2(2.45)=16.1

The width of the box is W=12-2(2.45)=7.1

So, Dimension of the box is 16.1\times 7.1\times 2.45

6 0
3 years ago
Is the ratio $81 in 9 hours equivalent to $63 in 7 hours
In-s [12.5K]
Yes they are equivalent because their ratio is 9
81/9= 9
63/7=9
3 0
3 years ago
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